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3 years ago

Divide 0.0081 by 300 seconds and express the answer in scientific notation.

Physics

1 answer:

Colt1911 [192]3 years ago

3 0

Answer:

4×10⁴ seconds

Explanation:

Assuming you have a calculator on hand, inputting 300 ÷ .0081 give should give you 37037.0370...

In scientific notation, that number would be 3.70370370...×10⁴ and when taking into account the rounding rules for significant figures, the answer is 4×10⁴ seconds.

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What is displacement

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Answer:

finding the volume of an irregular shape

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3 years ago

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Fill in the blanks to the statement below in the next three questions: A train composed of a small engine car and a massive carg

Assoli18 [71]

Answer:

1) is equal to, 2) is equal to, connected and moving along the same track.

Explanation:

1) The speed of the small engine car is equal to the speed of the massive cargo car.

2) The magnitude of the acceleration of the small engine car is equal to the magnitude of the acceleration of massive cargo car because they are connected and moving along the same track.

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4 years ago

If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the

Novosadov [1.4K]

Law of Conservation of Energy states that the total amount of energy remains constant in an isolated system and Energy can be neither created nor destroyed.

Therefore,
The refrigerator removed 272 Joules of energy from the food (making it colder) and dumped 272 J of energy outside (heat of the refrigerator).

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3 years ago

The speed of sound in air at room temperature is about s=343 m/s. calculate this speed in miles per hour (mph). (1 mi = 1609 m.)

igor_vitrenko [27]

Given:
1 mi = 1609 m.

Also,
1 hour = 3600 s

Therefore
$343 \, \frac{m}{s} =(343 \, \frac{m}{s} )*(3600 \, \frac{s}{h}) *( \frac{1}{1609}\, \frac{mi}{m})= 767.433 \, \frac{mi}{h}$

Answer: 767.4 mph (nearest tenth)

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4 years ago

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A 0.9 kg ball attached to a cord is whirled in a vertical circle of radius 2.5 m. Find the minimum speed needed at the top of th

lapo4ka [179]

Answer:

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Explanation:

By the Principle of Energy Conservation we understand that the minimum speed needed by the ball is that speed such that maximum height reached is equal to the diameter of the vertical circle, that is:

$K =U_{g}$ (1)

Where:

$K$ - Translational kinetic energy, measured in joules.

$U_{g}$ - Gravitational potential energy, measured in joules.

By definitions of translational kinetic and gravitational potential energies, we expand the equation above and clear the initial speed of the ball:

$\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g\cdot h$

$v = \sqrt{2\cdot g\cdot h}$ (2)

Where:

$m$ - Mass, measured in kilograms.

$v$ - Initial speed, measured in meters per second.

$g$ - Gravitational acceleration, measured in meters per square second.

$h$ - Maximum height of the ball, measured in meters.

If we know that $g = 9.807\,\frac{m}{s^{2}}$ and $h = 5\,m$ , then the initial speed of the ball is:

$v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}$

$v\approx 9.903\,\frac{m}{s}$

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

3 0

4 years ago