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HACTEHA [7]
3 years ago
6

For the following reaction, how much energy would be needed to produce 3 moles of Na2CO3? PLEASE show work. 2NaHCO3+85kJ yields

Na2CO3+H20+CO2
Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0
The given reaction is rewritten below,

    2NaHCO3 + 85kJ --> Na2CO3 + H2O + CO2

It can be concluded that every 2 moles of NaHCO3 one needs 85kJ of energy. To determine the amount of energy needed for 3 moles of NaHCO3, the concept of ratio and proportion may be used.

       (85 kJ/ 2moles NaHCO3) (3 moles NaHCO3)
     = 127.5 kJ

Answer: 127.5 kJ
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In each reaction box, place the best reagent from the list below. draw the intermediate compound.
Fynjy0 [20]

Answer:

Reagent A: PBr₃

Reagent B: Mg in Et₂O.

Explanation:

Hello,

In this case, your facing a problem in which a carboxylic acid is produced starting by an alcohol. More specifically, cyclopentanol must react with phosphorous tribromide in order to yield bromocyclopentane which is more likely to produce a carboxylic acid, therefore, reagent A is PBr₃.

On the other hand, by means of the production of the specified product, bromocyclopentane must react with carbon dioxide and magnesium in diethyl ether in acidic media to promote the production of the cyclopentanoic acid via the grignard reaction (substitution of the bromine by the carboxyle group), therefore, reagent B is Mg in Et₂O.

Best regards.

8 0
3 years ago
How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -&gt;<br> 4A1 + 302
Evgesh-ka [11]
<h3>Answer:</h3>

\displaystyle 40 \ mol \ Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 40 \ mol \ Al

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

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3 years ago
What happens when two positively charged objects move closer to each other?
Katena32 [7]

Answer: Objects with like charge repel each other.

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RideAnS [48]

Answer:

Explanation:

To find the mass percent composition of an element, divide the mass contribution of the element by the total molecular mass. This number must then be multiplied by 100% to be expressed as a percent.

3 0
3 years ago
Structure of isobutyl formate
Aliun [14]

Answer:

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Explanation:

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