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HACTEHA [7]
3 years ago
6

For the following reaction, how much energy would be needed to produce 3 moles of Na2CO3? PLEASE show work. 2NaHCO3+85kJ yields

Na2CO3+H20+CO2
Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0
The given reaction is rewritten below,

    2NaHCO3 + 85kJ --> Na2CO3 + H2O + CO2

It can be concluded that every 2 moles of NaHCO3 one needs 85kJ of energy. To determine the amount of energy needed for 3 moles of NaHCO3, the concept of ratio and proportion may be used.

       (85 kJ/ 2moles NaHCO3) (3 moles NaHCO3)
     = 127.5 kJ

Answer: 127.5 kJ
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svetoff [14.1K]

Answer:

Explanation:

There is a formula for this:

M = DRT/P where M = molar mass. This just derived from PV = nRT where you say n = grams/molar mass. However, just with this formula, we can get D which is density at STP (1 atm and 273K). We find that D = 6.52g/L.

7 0
3 years ago
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point)A chemist has 4.43 g of lithium carbonate and must make a 0.0600 mol/L solution.What volume of solution can be made?a) 0.0
ANTONII [103]

Explanation:

A chemist has 4.43 g of lithium carbonate and must prepare a 0.0600 mol/L (or 0.0600 M) solution. We have to find the volume of solution that can be made.

The molarity of a solution is defined like:

molarity = moles of solute/volume of solution in L

We already know the concentration of the solution (it is 0.0600 mol/L) and the volume is our unknown.

volume of solution in L = ?

molarity = 0.0600 mol/L

We still have to convert the mass of lithium carbonate into moles. To do that we will use the molar mass of the compound.

lithium carbonate = Li₂CO₃

mass of Li₂CO₃ = 4.43 g

molar mass of Li₂CO₃ = 73.89 g/mol

moles of Li₂CO₃ = 4.43 g * 1 mol/(73.89 g)

moles of Li₂CO₃ = 0.0600 moles

Finally we can replace the values in the formula and solve it for the volume of solution.

molarity = moles of solute/volume of solution in L

volume of solution in L = moles of solute/molarity

volume of solution in L = 0.0600 mol/(0.0600 mol/L)

volume of solution in L = 1.00 L

Answer: b) 1.00 L

3 0
1 year ago
Potassium-40 has a half-life of 1.277 mc013-1.jpg 109 years. After 1.022 mc013-2.jpg1010 years, how much potassium-40 will remai
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8 0
4 years ago
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Help asap plz its a test
Alex_Xolod [135]

Answer:

B

Explanation:

4 0
3 years ago
Inside a car that was at STP, a 1.33 L bottle warms up to 130 C. If the volume of the bottle remains constant, what is the press
fiasKO [112]

Answer:

P_2=1.48atm

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to infer this problem is about the application of the Gay-Lussac's gas law to relate the initial and final pressure and temperature as shown below:

\frac{P_2}{T_2} =\frac{P_1}{T_1\\ }

Thus, solving for the final pressure, P2, and using the temperatures in Kelvins, we obtain:

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Regards!

7 0
3 years ago
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