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serious [3.7K]
3 years ago
10

A toy boat is floating in a large metal bucket. If you build a fire under the bucket, how the heat will transfer from the fire t

o the boat?
A. Water molecules in the bucket will transfer the heat.
B. Metal molecules of the bucket will transfer the heat.
C. Surrounding air molecules will transfer the heat.
Chemistry
2 answers:
IrinaK [193]3 years ago
7 0

A.  Water molecus in the bucket will transfer the heat.

Solnce55 [7]3 years ago
3 0
A. The water molecules in the bucket will heat the water and the water will heat the boat 
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Arrange the following measurements, in seconds, from the greatest bias to the least bias. 6.63 ± 0.01 s, 6.6 ± 0.1 s, 6.52 ± 0.0
lord [1]
I understand here "bias" to be the uncertainty of measurements. So the order will be the following:

6.4 ± 0.5 s
<span>6.6 ± 0.1 s,
</span><span>6.63 ± 0.01 s,
</span><span>6.52 ± 0.05 s,
</span>
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6 0
4 years ago
A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant
KiRa [710]

Answer:

V_2=2.995L\\\\W=248.5J

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

P_1V_1=P_2V_2

So we solve for V_2 by firstly computing the initial pressure:

P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L}  =11.98atm

V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L

Finally, we can compute the work by using the following formula:

W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J

Best regards.

4 0
3 years ago
What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid at 0°C?
Marrrta [24]
Energy released from changing the phase of a substance from the liquid phase to solid phase can be calculated by using the specific latent heat of fusion. The heat of fusion of water at 0 degrees Celsius is 334 J/g. Calculation are as follows:
<span>
Energy = 5 grams x 334 J/g
</span><span>Energy = 1670 J</span>
4 0
3 years ago
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