C. The heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
<h3>What is Specific heat capacity?</h3>
Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass.
<h3>
Heat released when the aluminum is cooled </h3>
The heat released when the aluminum is cooled from 70°C to 50°C is calculated as follows;
Q = mcΔθ
where;
- m is mass of the aluminum
- c is specific heat capacity
- Δθ is change in temperature
Q = (10)(0.9)(50 - 70)
Q = -180 J
Thus, the heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
Learn more about heat capacity here: brainly.com/question/16559442
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<u>Answer:</u> For the given equation, only iron has the value of 
equal to 0 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28reactant%29%5D)
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28Fe%28s%29%29%7D%29%2B%283%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%29%5D-%5B%283%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO%28g%29%29%7D%29%2B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28Fe_2O_3%28s%29%29%7D%29%5D)
The enthalpy of formation for the substances present in their elemental state is taken as 0.
Here, iron is present in its elemental state which is solid.
Hence, for the given equation, only iron has the value of equal to 0 kJ.
If the number of electron is more than the protons,the atom is negative
if the number of electrons is less than the protons, the atom will be positive
The chemical formulas for their respective substances are the following:
Cadmium Sulfide: CdS
Sulfuric Acid: H₂SO₄
Hydrogen Sulfide: H₂S
This is a double replacement reaction where the substances of the reactants interchange to yield two products. The complete balance reaction would be:
<span>CdS (s) + H</span>₂<span>SO</span>₄<span> (aq) ----> CdSO</span>₄<span> (aq) + H</span>₂<span>S (g)
</span>
The other product is Cadmium Sulfate.
D. Should be correct- the other ones don’t make sense
