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3 years ago

Which is an example of a solution?

Chemistry

2 answers:

Jlenok [28]3 years ago

5 0

It is definitely c bruh

Rudiy273 years ago

3 0

The answer is C. Salt and water is a solution

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3 points

vfiekz [6]

Answer:

density=6.74g/ml

:320g÷47.5ml

d=6.74g/ml

thank you

I hope this is helpful

8 0

3 years ago

Label each statement with its corresponding type of scientific knowledge.

Marrrta [24]

Label each statement with its corresponding type of scientific knowledge.

law

theory

fact

hypothesis

The melting point of ice is 0°C: thus is a fact based on repetitive experiments

Repeated observations have consistently

shown that oppositely charged objects

attract each other: this is law

When the elements carbon and nitrogen

are mixed at 1500°C, they will react

with each other.

this is a hypothesis

Atoms are made of protons, neutrons,

and electrons. Although we can’t directly

see these particles, this structure

explains many experimental observations

Theory

8 0

3 years ago

Read 2 more answers

Why can't we separate azeotropes with the distillation process?.

liraira [26]

Answer:

have just recently learnt the theory of fractional and normal distillations and the basics of maximum and minimum boiling azeotropes.

6 0

2 years ago

What distance in kilometers can you drive if your car gets 14.00 kilometers per liter and you have 35.00 liters of gas?

agasfer [191]

2.5 km is the distance you can travel if a car gets 14 kilometers per liter and have 35 liters of gas.

Total distance traveled in 1 liter = 14 km

Total gas in the car = 35 liters

We have to find how much distance can be covered in in35 liters of gas.

Distance is the length of the path traveled between two points. It is the total movement of an object in a direction. It measures length.

Distance = 35/14

Or, distance = 2.5 km

Therefore, the total distance that can be covered by a car in 35 liters of gas is 2.5 km.

To learn more about distance, visit: brainly.com/question/15172156

#SPJ9

7 0

1 year ago

A 150.0 mL sample of an aqueous solution at 25°C contains 15.2 mg of an unknown nonelectrolyte compound. If the solution has an

inysia [295]

Answer: The molar mass of the unknown compound is 223.2 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

where,

$\pi$ = osmotic pressure of the solution = 8.44 torr

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = ?

R = Gas constant = $62.3637\text{ L torr }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$8.44torr=1\times M\times 62.3637\text{ L. torr }mol^{-1}K^{-1}\times 298K\\\\M=\frac{8.44}{1\times 62.3637\times 298}=4.54\times 10^{-4}M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = $4.54\times 10^{-4}M$

Given mass of unknown compound = 15.2 mg = 0.0152 g (Conversion factor: 1 g = 1000 mg)

Volume of solution = 150.0 mL

Putting values in above equation, we get:

$4.54\times 10^{-4}M=\frac{0.0152\times 1000}{\text{Molar mass of unknown compound}\times 150.0}\\\\\text{Molar mass of unknown compound}=\frac{0.0152\times 1000}{150.0\times 4.54\times 10^{-4}}=223.2g/mol$

Hence, the molar mass of the unknown compound is 223.2 g/mol

5 0

3 years ago