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Amanda [17]
1 year ago
12

Q2. Name, constituent of petroleum (Petrochemicals) which is used for following purposes.

Chemistry
1 answer:
finlep [7]1 year ago
7 0

The constituents of petroleum that are used for the following purposes are as follows:

  • To make candles ----- Paraffin wax
  • A solvent for dry cleaning ----- Petrol
  • For surfacing roads ----- Bitumen
  • Jet engine fuel ----- Kerosene
  • For lubrication ----- Lubricating oil.

<h3>What are the constituents of petroleum?</h3>

The constituents of petroleum are LPG, bitumen, paraffin wax, lubricating oil, kerosene, diesel, etc. These compounds are a mixture of hydrocarbons.

Therefore, each constituent of petroleum that is used for the following purposes is mentioned above with proper names.

To learn more about constituents of petroleum, refer to the link:

brainly.com/question/17023299

#SPJ1

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When 1 mol of sodium nitrate, is dissolved in 1 cubic decimeter of water, 40 kJ of heat energy is absorbed. What is the drop in
vesna_86 [32]

Answer:

 1.0  ° C

Explanation:

The molar mass for Sodium Nitrate NaNO₃ = (23+14+(16×3)) = 85

Number of moles of NaNO₃  = mass of NaNO₃ /molar mass of NaNO₃

⇒ 17/85 = 1.38 moles

Since 1 mole of NaNO₃  dissolved in 1 cubic decimeter of water, 40 kJ of heat energy is absorbed.

when 1.38 mole of NaNO₃  dissolved in 1 cubic decimeter of water, x kJ of heat energy is absorbed..

Then; x kJ of 1.38 mole of NaNo₃ = 1.38 × 40 kJ  =55.2 kJ of heat absorbed.

Using the relation : Q = mcΔT  to determine the temperature drop ; we get:

55.2 = 17 × 4 (ΔT)

55.2  = 68 ΔT

ΔT= 0.8 ° C

ΔT ≅  1.0  ° C

Therefore, the drop in temperature when 17.0g of sodium nitrate is dissolved in 1 cubic decimeter of water is   1.0  ° C

7 0
2 years ago
The by-product of the chlorination of an alkane is​
Elanso [62]

The by-product of the chlorination of an alkane is​  <u>HCl</u>

Explanation:

  • Chlorination is the process of adding chlorine to drinking water to disinfect it and kill germs. Different processes can be used to achieve safe levels of chlorine in drinking water.
  • Chlorination of alkane gives a mixture of different products.
  • When consider mechanism of alkanes chlorination, free radicals are formed during the reaction to keep the continuous reaction.
  • Different alkyl chloride compounds, extended carbon chains compounds and HCl are formed as products in product mixture.
  • Chlorination byproducts, their toxicodynamics and removal from drinking water.
  • Halogenated trihalomethanes (THMs) and haloacetic acids (HAAs) are two major classes of disinfection byproducts (DBPs) commonly found in waters disinfected with chlorine
  • Chlorine is available as compressed elemental gas, sodium hypochlorite solution (NaOCl) or solid calcium hypochlorite (Ca(OCl)2
7 0
3 years ago
What happens to the density of a substance when it is heated? Explain your answer.
hoa [83]

Heating a substance causes molecules to speed up and spread slightly further apart, occupying a larger volume that results in a decrease in density. Cooling a substance causes molecules to slow down and get slightly closer together, occupying a smaller volume that results in an increase in density.

From: www.middleschoolchemistry.com

7 0
3 years ago
Q4
Varvara68 [4.7K]

Answer:

Option C.

Ilegal dumping of waste

Explanation:

This is because non point source of pollution refers to source of pollution that are many and not directly one which is illegal or does not meet the legal term. This type of pollution does not have a point source, it has many sources and this type of pollution is cause by rainfall or precipitation. Where when the rain fall, it wash away the waste through to water bodies, causing pollution and endangering water bodies.

3 0
3 years ago
Hi, can someone help me balance this chemistry equation:<br> H2SO4 + RbOH -&gt; Rb2SO4 + H2O
zloy xaker [14]

H2SO4 + 2RbOH -> Rb2SO4 + 2H2O

If you want an explanation, keep reading.

In the first portion, there are two hydrogen ions and four sulfate ions.

The second portion has one rubidium ions and one hydroxide ion.

On the other side of the equation, in order to keep those two rubidiums balanced, you'll need to add a two at the beginning of the second portion, but in that process you are giving a second hydroxide value.

Back to the right side, there is there is water (H2O).

On the first portion, there were two hydrogen ions. The second portion also has two hydroxides because of the value change (adding the two to the front).

So on the fourth portion, you'd have to add another two so you could balance the four hydrogen ions (H2 and 2OH) and the two oxygen ions (2OH).

I hope this was easy to understand.

6 0
3 years ago
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