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Amanda [17]
2 years ago
12

Q2. Name, constituent of petroleum (Petrochemicals) which is used for following purposes.

Chemistry
1 answer:
finlep [7]2 years ago
7 0

The constituents of petroleum that are used for the following purposes are as follows:

  • To make candles ----- Paraffin wax
  • A solvent for dry cleaning ----- Petrol
  • For surfacing roads ----- Bitumen
  • Jet engine fuel ----- Kerosene
  • For lubrication ----- Lubricating oil.

<h3>What are the constituents of petroleum?</h3>

The constituents of petroleum are LPG, bitumen, paraffin wax, lubricating oil, kerosene, diesel, etc. These compounds are a mixture of hydrocarbons.

Therefore, each constituent of petroleum that is used for the following purposes is mentioned above with proper names.

To learn more about constituents of petroleum, refer to the link:

brainly.com/question/17023299

#SPJ1

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For alpha decay to cause a loss in mass, such as that in the uranium 238 conversion to thorium 234, what must the atomic weight
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Explanation:

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1.65g of zinc is used to make 8g of zinc iodide. How much iodine is required for this reaction?
creativ13 [48]

Answer:

6.45 g of iodine, I₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + I₂ —> ZnI₂

Next, we shall determine the mass of Zn and I₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

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Mass of I₂ from the balanced equation = 1 × 254 = 254 g

SUMMARY:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Finally, we shall determine the mass of f I₂ needed to react with 1.65 g of Zn. This can be obtained as follow:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Therefore, 1.65 g of Zn will react with = (1.65 × 254)/65 = 6.45 g of I₂.

Thus, 6.45 g of iodine, I₂ is needed for the reaction.

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