Answer:
- last option: none of<u> the above.</u>
Explanation:
Describing a solution as<em> concentrated</em> tells that the solution has a relative large concentration, but it is a qualitative description, not a quantitative one, so this does not tell really how concentrated the solution is. This is, the term concentrated is a kind of vague; it just lets you know that the solution is not very diluted, but, as said initially, that there is a relative large amount (concentration) of solute.
One conclusion, of course, is that <u>the solute is soluble</u>: else the solution were not concentrated.
On the other hand, the terms saturated and <em>supersaturated</em> to define a solution are specific.
A saturated solution has all the solute that certain amount of solvent can contain, at a given temperature. A <u>supersaturated solution has more solute dissolved than the saturated solution</u> at the same temperature; superstaturation is a very unstable condition.
From above, there is no way that you can conclude whether a solution is supersaturated or not from the statement that a solution is concentrated, so the answer is<u> none of the above</u>.
Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
- In order to respond to this query, we must decide whether a peptide bond or an aromatic side chain is demonstrating an electronic exited state that is more closely related to the ground state in terms of energy.
- When our energy is as low as possible, we are in the ground state.
- What I want to point out is that if we can choose between the two options—peptide bond or aromatic side chain—without knowing the specific reasons, we can immediately rule out two potential answers.
- Consider what we already know about energy, we have:
E = h x c/λ
- That indicates that when we have more energy, a wavelength decreases. Lower energy corresponds to higher wavelength.
- Aromatic side chains absorb between 250 and 290 nm, while peptide bonds do so between 190 and 250 nm.
- According to our breakdown, we have an electron excited state that is more closely related to the ground state in terms of energy as wavelength increases.
Thus, Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
To view similar questions about energy, refer to:
brainly.com/question/14483627
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Answer: hello attached below is the complete question
answer :
attached below
Explanation:
Diagram of the all the observed products are attached below
note: through radical mechanism The free radicals are stabilized by resonance
Attached below
this is due to the difference in electron density. Butylamine has more electron density than ammonia. Due to this reason is a Butylamine stronger base than ammonia. BUtylamine has positive induction effect of -CH3 group electron density on N atom which increases
Answer:
12.5 moles H2SO4
Explanation:
Calculate the amount, in moles, of 2.5 L of a 5.0 M sulfuric acid, H2SO4.
5.0 M means 5 moles per liter.
so in 2.5 L we have
5.0 X 2.25 = 12.5 moles H2SO4
