Ask question

Ask question

All categories

3 years ago

12

In the equation F = Kq1 q2/r2 solve for q2. Solve for r.

1 answer:

Tpy6a [65]3 years ago

3 0

Answer:

r = √(k q₁ q₂ / F)

Explanation:

F = k q₁ q₂ / r²

Multiply both sides by r²:

F r² = k q₁ q₂

Divide both sides by F:

r² = k q₁ q₂ / F

Take the square root of both sides:

r = √(k q₁ q₂ / F)

You might be interested in

List and define all of Newton’s laws of motion.

Luba_88 [7]

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

6 0

2 years ago

What is force ? <br>question for spammers hehe..

love history [14]

Answer:

Force: Strength or energy as an attribute of physical action or movement.

6 0

3 years ago

Read 2 more answers

The photons of different light waves:

LuckyWell [14K]

Answer: contain different amounts of energy

Explanation:

The energy $E$ of a photon is given by:

$E=h\nu$

Where:

$h=6.626(10)^{-34}\frac{m^{2}kg}{s}$ is the Planck constant

$\nu$ is the frequency of the light which is inversely related to the wavelength.

Now, if we have photons of different light waves, this means we have photons with different frequencies.

As the energy of the photon depends on its frequency:

Photons of different light waves <u>contain different amounts of energy.</u>

8 0

3 years ago

Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.5000 kgkg when weighed in air. The density o

spin [16.1K]

Answer:

The true weight of the aluminium is $m_{alu} =$ 4.5021 kg

Explanation:

Given data

$m_{app}$ = 4.5 kg

$\rho_{air}$ = 1.29 $\frac{kg}{m^{3} }$

$\rho_{al}$ = 2.7× $10^{3} \frac{kg}{m^{3} }$

The true mass of the aluminium is given by

$m_{alu} = \frac{\rho_{alu}m_{app}}{\rho_{alu} -\rho_{air} }$

Put all the values in above equation we get

$m_{alu} = \frac{(2700)(4.5)}{2700-1.29}$

$m_{alu} =$ 4.5021 kg

Therefore the true weight of the aluminium is $m_{alu} =$ 4.5021 kg

6 0

3 years ago

WILL GIVE BRAINLIEST

NemiM [27]

Yes! you are :) bc you are FORCING the page to turn, and the broom ti sweep

6 0

3 years ago

Read 2 more answers