The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
where
is the angle between the directions of v and B.
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
. In this case, v and B are perpendicular, so
, therefore we have:
2) In this second case, the angle between v and B is
. The charge is now
, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
<span>When a magnet moves near a wire, it's changing field causes the electrons in the wire to flow as electric current.</span>
Answer:
Increase the charge of one particle by a factor of 16
Explanation:
Neither because if driver 2 hadn't stopped, they both would've finished in the same amount of time.