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Contact [7]
3 years ago
9

What term describes the rate at which charge passes a point in a circuit

Physics
2 answers:
docker41 [41]3 years ago
8 0
That's electric "current", usually described in 'Amperes'.

1 Ampere = 1 Coulomb per second ... "the rate at which
charge passes a point in the circuit".
mixer [17]3 years ago
8 0

Current - APEX :) lol it said my answer wasn't long enough so yeah Hi

You might be interested in
Use the techniques to find the unit for speed​
stellarik [79]

Answer:

The formula for speed is speed=<u>d</u><u>i</u><u>s</u><u>t</u><u>a</u><u>n</u><u>c</u><u>e</u>

time

Explanation:

to work out what the units are for speed,you need to know the units for distance and time.In this example,distance is in metres(m) and time is in seconds (s) , so the units for speed is metre per second (m/s).

8 0
3 years ago
Read 2 more answers
Luis and Aisha conducted an experiment. They exerted different forces on four objects. Their results are shown in the table.
lesya692 [45]

Answer:

Object 3 has greatest acceleration.

Explanation:

Objects               Mass                                Force

1                            10 kg                               4 N              

2                           100 grams                       20 N

3                            10 grams                         4 N

4                             1 kg                                 20 N

Acceleration of object 1,

a_1=\dfrac{F_1}{m_1}\\\\a_1=\dfrac{4}{10}\\\\a_1=0.4\ m/s^2

Acceleration of object 2,

a_2=\dfrac{F_2}{m_2}\\\\a_2=\dfrac{20}{0.1}\\\\a_2=200\ m/s^2

Acceleration of object 3,

a_3=\dfrac{F_3}{m_3}\\\\a_3=\dfrac{4}{0.01}\\\\a_3=400\ m/s^2

Acceleration of object 4,

a_4=\dfrac{F_4}{m_4}\\\\a_4=\dfrac{20}{1}\\\\a_3=20\ m/s^2

It is clear that the acceleration of object 3 is 400\ m/s^2 and it is greatest of all. So, the correct option is (3).

4 0
3 years ago
Read 2 more answers
A -kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the tra
Tatiana [17]

Answer:

The centripetal acceleration of the car is 8\ m/s^2.

Explanation:

Let the mass of the car, m=10^3\ kg

Diameter of the circular path, d = 100 m

Speed of car, v = 20 m/s

Radius, r = 50 m

When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(20\ m/s)^2}{50\ m}

a=8\ m/s^2

So, the centripetal acceleration of the car is 8\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
A person's _____________ will change if they move from the Earth to the moon.
Diano4ka-milaya [45]

1. A person's weight will change if they move from the Earth to the moon.

In fact, the weight of a person is given by:

W=mg

where m is the mass of the person and g is the gravitational acceleration. The mass of the person, m, is the same on the Earth and on the moon, but the value of g is different on the Moon (about 1/6 of the Earth's value), so the weight also changes.


2. An astronaut is launched into space. The mass of the astronaut did not change. This is measured in Kg.

The mass of an object (or of a person, as in this case) is an intrinsec property of the object, that depends on the amount of matter inside the object: therefore, this quantity does not depend on the location of the object, so it is the same on the Earth, on the Moon and in space.


3. What is the weight of a ring tailed lemur that has a mass of 10 kg? -98 N

The weight of the lemur is given by:

W=mg

where m=10 kg is the lemur's mass and g=-9.8 m/s^2 is the gravitational acceleration. Using these numbers, we find

W=(10 kg)(-9.8 m/s^2)=-98 N

and the negative sign simply means that the direction of the weight is downward.


4. What is the mass of the lemur from the previous question if it was on the International Space Station? 10 kg

As we said in question 1), the mass of an object does not depend on the location, so the mass of the lemur is still 10 kg, as in the previous exercise.


5. A rocket being thrust upward as the force of the fuel being burned pushes downward is an example of which of Newton's laws? Third's Newton Law

Third's Newton Law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".

Applied to this case, the two objects are the fuel and the rocket. The fuel is pushed backward by the rocket, so the fuel exerts an equal and opposite force on the rocket, which then moves forward.


6. When a cannon is fired, the projectile moves forward. According to Newton's 3rd law, the cannon will want to travel backward.

Third's Newton Law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".

Applied to this case, the two objects are the cannon and the projectile.The projectile is pushed forward by the cannon, so the projectile exerts an equal and opposite force on the cannon, which moves backward.


7. An object has a weight of 21,532 N on Earth. What is the mass of the object? 2,197 kg

The weight of the object is given by: W=mg

If we re-arrange the formula and we use W=21,532 N, we can find the mass of the object:

m=\frac{W}{g}=\frac{21,532 N}{9.8 m/s^2}=2,197 kg


8. What is the mass of the object from the previous question if we put it on the moon? The force of gravity on the moon is 1.62 m/s2.  2,197 kg

As we said in question 4), the mass of an object does not change if we move it to another location, so its mass is still 2,197 kg.


9. How much force is exerted if a 250 kg object has an acceleration of 750 m/s2 ? 187,500 N

The force exerted on the object is given by Newton's second law:

F=ma

where F is the force, m=250 kg is the mass and a=750 m/s^2 is the acceleration. By using these numbers, we find

F=(250 kg)(750 m/s^2)=187,500 N


10. A resting soccer ball moving after it is kicked is an example of which of Newton's laws? Newton's second law

Newton's second law states that when an object is acted upon unbalanced force, the object has an acceleration, given by the law

F=ma

So, in this case, the ball is kicked and so an unbalanced force is applied to it, and for this reason the ball has an acceleration (in fact, it starts from rest, but then its velocity increases since it starts moving).

5 0
2 years ago
I need to know the right answer to that question
ad-work [718]
The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)

Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation

v = vo + at

When you plug in the values you get

v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.
8 0
3 years ago
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