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3 years ago

What term describes the rate at which charge passes a point in a circuit

2 answers:

8 0

That's electric "current", usually described in 'Amperes'.

1 Ampere = 1 Coulomb per second ... "the rate at which
charge passes a point in the circuit".

mixer [17]3 years ago

8 0

Current - APEX :) lol it said my answer wasn't long enough so yeah Hi

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A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing a

hodyreva [135]

Answer:

5 m/s2

Explanation:

The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.

The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle

$a_c = \frac{v^2}{r} = \frac{30^2}{300} = \frac{900}{300} = 3 m/s^2$

So the magnitude of the total acceleration is

$a = \sqrt{a_c^2 + a_l^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 m/s^2$

4 0

3 years ago

A sailboat weighing 980 lb with its occupants is running downwind at 8 mi/h when its spinnaker is raised to increase its speed.

Effectus [21]

Answer:

78.498N

Explanation:

The Net force provided by the spinnaker can be obtained from Newton's second law of motion as follows;

$F=\frac{m(v-u)}{t}................(1)$

where m is the mass, v is the final velocity, u is the initial velocity and t is the time interval for which the force acted.

Given;

m =980lb

v = 12mi/h

u =8mi/hr

t = 10s.

It is important to convert all quantities to their SI units where necessary, so we do that as follows;

1lb = 0.45kg,

hence 980lb = 980 x 0.45kg = 441kg.

1mile = 1609.34m

1hour = 3600s,

therefore;

$8mi/h=\frac{8*1609.34m}{3600s}=3.58m/s$

$12mi/h=\frac{12*1609.34m}{3600s}=5.36m/s$

Substituting all values into equation (1), we obtain the following;

$F=\frac{441(5.36-3.58)}{10}\\F=\frac{441*1.78}{10}\\F=\frac{784.98}{10}\\F=78.498N$

4 0

3 years ago

The train took 2 h 30 min to travel 3/5 of a journey at an

tresset_1 [31]

Answer:

100 km/h

Explanation:

96km•2.5=240km

240÷3/5=240•5/3=400km

400-240=160km

4.1-2.5=1.6h

160÷1.6=100km/h

6 0

3 years ago

6A certain load and set of slings create a 20-degree angle between the load and each sling leg. Using a spreader for the same li

Otrada [13]

Solution:

The angle between the sling and the load is $20^{\circ}$

So the tension in each sling can be calculated as

$Sin \theta = Mg => T = \frac{Mg}{2Sin\theta}$

$Sin \theta=> \frac{Mg}{2Sin 20^{\circ}}$

Where

M is the mass of the load

The Horizontal reaction on the sling will be inward.

After using the spreader, the new angle between sling and load is $60^{\circ}$ , the tension in the sling will be

$T= \frac{Mg}{2 Sin 60^{\circ}}$ = $\frac{Mg}{2 Sin 20^{\circ}}$

The tension will be same as before in the sling move away through the spreader at an angle more than 90 degree the horizontal force will act opposite and will be outward

5 0

3 years ago

Starting from rest, a particle moving in a straight line has an acceleration of a = (2t - 6) m/s^2, where t is in seconds. What

hjlf

To solve this problem we will use the given expression and derive it in order to find the algebraic expressions of velocity and position. These equations will be similar to those already known in the cinematic movement but will be subject to the previously given function. We start deriving the equation for velocity

$a = 2t-6$