The spring potential energy is 1.6 J
Explanation:
The elastic potential energy of a spring is given by the equation:
where
U is the potential energy
k is the spring constant
x is the compression/stretching of the spring
For the spring in this problem, we have:
x = 40 cm = 0.40 m is the stretching
k = 20 N/m is the spring constant
Substituting into the equation, we can find the spring potential energy:
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Answer:
(a) Projectile B will travel 4 times as far as projectile A prior to landing
Explanation:
Initial velocity = v
Angle at which the projectile is shot at = θ
g = Acceleration due to gravity
Range of a projectile is given by
When Initial velocity = v
When Initial velocity = 2v
Dividing the equtions, we get
Here, the angle at which the projectiles are fired at are equal.
Hence, projectile B will travel 4 times as far as projectile A prior to landing