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3 years ago

What are some facts about visual memory

2 answers:

7 0

* Is the ability to remember facts or stuff based on what you've seen.
*Eskimo children from villages have a really good visual memory
*Sleeping well helps to improve it

mr_godi [17]3 years ago

5 0

<span> Learning new things produces physical changes in your brain structure</span>

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Describe the main distinguishing features of spiral, elliptical, and irregular galaxies.

hram777 [196]

Answer:

Spiral galaxies consist of a flat, rotating disk of stars, gas and dust, and a central concentration of stars known as the bulge. These are surrounded by a much fainter halo of stars, many of which reside in globular clusters.

Elliptical galaxies have smooth, featureless light-profiles and range in shape from nearly spherical to highly flattened, and in size from hundreds of millions to over one trillion stars. In the outer regions, many stars are grouped into globular clusters. Most elliptical galaxies are composed of older, low-mass stars, with a sparse interstellar medium and minimal star formation activity They are often chaotic in appearance, with neither a nuclear bulge nor any trace of spiral arm structure. Collectively they are thought to make up about a quarter of all galaxies.

irregular galaxies were once spiral or elliptical galaxies but were deformed by gravitational action. they are shapeless.

5 0

3 years ago

Bill and Ted are standing on a bridge 40 ft above a river. Bill drops a stone, while Ted decides to throw a stone downward at 10

USPshnik [31]

Answer:

Explanation:

In order to know how long after Bill released his rock should Ted throw his if they want the stones to hit the water simultanously, we need to calculate the time needed to hit the water to both rocks independent each other, and just take the difference.

For the rock dropped by Bill, as the only influence on it is gravity (accelerating it downwards with an acceleration equal to g), and v₀ =0, we can use the following kinematic equation:

$y = \frac{1}{2} * g * t^{2}$

where y = height = 40 ft.

As all the parameters are given in SI units, it is advisable to convert this value to m, as follows:

$y = 40 ft*\frac{0.3048m}{1 ft} = 12.2 m$

Now, we can solve for t, as follows:

$t = \sqrt{\frac{2*y}{g}} = \sqrt{\frac{2*12.2m}{9.8m/s2}} = 1.58 s$

For the rock thrown down at 10 m/s, the kinematic equation we just have used becomes:

$y = v0*t +\frac{1}{2} * g * t^{2}$

This leaves us a quadratic equation on t, as follows:

$t = \frac{-10m/s}{9.8m/s2} +/- \sqrt{10m/s^{2} -4*4.9m/s2*(-12.2m)} = -1.02 s +/- 1.88s$

Taking the positive root, we have:

t = -1.02 s + 1.88 s = 0.86 s

So, in order to get that both rocks hit the water at the same time, Ted will need to wait the difference between both times:

Δt = 0.86 s - 1.58s = -0.72 s

5 0

3 years ago

Dynamic stretching serves 2 purposes warming up and controlling BMI true or false

Ket [755]

Uhm i think false but i’m not sure

8 0

2 years ago

Why is the gravitational force usually ignored in problems involving particles such as electrons and protons?

Studentka2010 [4]

Answer:

Because the mass of electrons and protons is very small

Explanation:

The gravitational force exerted between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

m1 and m2 are the masses of the two objects

r is the distance between the two objects

The mass of a proton and of an electron is very small, so the gravitational force involved in case of such particles is very weak. Let's calculate for example the gravitational attraction between one proton and one electron at a distance of r = 1 m. We have:

- Proton mass: $m_1 = 1.67 \cdot 10^{-27}kg$

- Electron mass: $m_2 = 9.11\cdot 10^{-31}kg$

So, the gravitational force between the two particles is:

$F=(6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2})\frac{(1.67\cdot 10^{-27}kg)(9.11\cdot 10^{-31} kg)}{(1 m)^2}=1.01\cdot 10^{-67}N$

Which is a very weak force.

By comparison, let's calculate instead the electromagnetic force between a proton and an electron (both having a charge of $q=1.6\cdot 10^{-19}C$ ) still separated by a distance of r = 1 m. We have:

$F=k\frac{q_1 q_2}{r^2}=(9.0\cdot 10^9 Nm^2C^{-2})\frac{(1.6\cdot 10^{-19}C)(1.6\cdot 10^{-19}C)}{(1 m)^2}=2.3\cdot 10^{-28}N$

Which we see is much stronger than the gravitational force (almost by a factor $10^{40}$

4 0

3 years ago

Please answer it i need the answer

Damm [24]

I never did that right there

6 0

3 years ago