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Vladimir79 [104]
3 years ago
7

A cat has a mass of 4.6 kg. What is its weight on Earth's surface?

Physics
2 answers:
kap26 [50]3 years ago
6 0

Answer:

Choice b is correct answer.

Step-by-Step explanation:

We have given the mass of a cat.

mass = m = 4.6kg

We have to find the  weight of cat on earth' surface.

The formula to find weight is:

weight = mass × gravity

w = mg

The value of gravity on earth surface is 9.8 m/sec².

Putting values in above formula, we have

w = 4.6 × 9.8 (kgm/sec²)              ∴   kgm/sec²  =  Newtons

w = 45 Newtons which is the answer.

andreyandreev [35.5K]3 years ago
4 0
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Earth's gravity is approximately 9.81

weight = mass x gravity

weight = 4.6 x 9.81

weight = 45.126

Answer is B. 45N

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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2 years ago
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La masa de un objeto en la tierra es de 100 kg.
andreev551 [17]

Answer:

a) 980 N

b) 100 kg

c)  163.33 N

Explanation:

a)

The weight of the object on Earth is the product of its mass times the acceleration due to gravity, that is:

W=m\,g=(100\,\,kg)\,g=(100\,\,kg)\,(9.8\,\,m/s^2)=980\,\,N

b)

The mass of the object on the moon, is exactly the same (100 kg) since mass is an inherited value of the object.

c)

Considering that the acceleration of gravity on the Moon is about 1/6 that we have on earth (g), then the weight of the object on the Moon becomes:

W=m\,\frac{g}{6} =\frac{980}{6}\,\,N=163.33\,\,N

3 0
3 years ago
Find the velocity at which the bowling ball must move for its kinetic energy to be equal to that of the meteorite.
Vikentia [17]

Answer:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

Explanation:

BOOM!!!

7 0
3 years ago
WILL MARK BRAINLIESTFor the simple harmonic motion equation d =4sin(8pit) what is the period?
shtirl [24]
The period of any wave is the time it takes for its angle
to go from zero to 2pi .

The 'sin' function is a wave.  The angle of this one is (8pi t).

When t=0, the angle is zero.
Wonderful.
Now, how long does it take for the angle to grow to 2pi ?

I*n other words, when is (8pi t) = 2pi ?

Divide each side by '2pi': . . . . . 4 t = 1

Divide each side by ' 4 ': . . . . . t = 1/4

And there you are.  Every time 't' grows by 1/4, (8pi t) grows by 2pi.
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4 0
3 years ago
An airplane is flying in a horizontal circle at a speed of 480 km/h. If its wings are tilted 40° to the horizontal, what is the
guajiro [1.7K]

Answer:

r = 2161.9 m

Explanation:

Aerodynamic lift(L) is perpendicular to the wing, which is tilted 40 degrees to the horizontal.

Since the plane is moving in a horizontal circle, the vertical component of the lift must cancel the weight W of the airplane, but the horizontal component is the centripetal force that keeps it in a circle.

L is perpendicular to wing at angle θ with respect to horizontal

Thus,

Vertical component of lift is:

L cosθ = W = mg

Thus, m = L cosθ / g - - - - (eq1)

Horizontal component of lift is:

L sinθ = centripetal force = mv² / r - - - - (eq2)

Combining equations 1 and 2,we have;

L sinθ = (L cosθ / g)(v² / r)

L cancels out on both sides to give;

tanθ = v²/ rg

r = v² / (g tanθ)

We are given;

velocity; v = 480 km/hr = 480 x 10/36 = 133.33 m/s

r = 133.33²/[(9.8) tan(40)] = 2161.9 m

3 0
3 years ago
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