All categories

3 years ago

Michael is taking a 500 mile road trip if he is 48% of the way there how many miles has he driven

Physics

2 answers:

Tju [1.3M]3 years ago

6 0

Answer

240

Explanation:

All you have to do is 500 times the decimal form of 48% which is .48 and you will get your answer.

You could also do 500 times 48 divided by 100

Elan Coil [88]3 years ago

5 0

fffff\

Answer:

Explanation:

ffdfffd

You might be interested in

What happens in the process of gravitational condensation?

Lerok [7]

Answer:

An object decreases in size due to the collision of materials. An object increases in size due to the addition of materials. Gas particles are formed from solar nebula materials.

3 0

4 years ago

What keeps both the cars pressed down on the road?

mihalych1998 [28]

Answer:

Gravity

Explanation:

5 0

3 years ago

In a chemical reaction, one element replaces another element in a compound to form a new substance. Which of the following best

Andreyy89

Answer:

single replacement

Explanation:

In the question it says one element replaces another element which means there is only one replacement.

3 0

3 years ago

Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she

Alex777 [14]

Answer

$200km {h}^{ - 2}$

Explanation

$Acceleration = \frac{final \: \: \: velocity - initial \: \: velocity }{time} \\ = \frac{(40 - 30)km {h}^{ - 1} }{0.05h} \\ = \frac{10}{0.05} \\ = 200km {h}^{ - 2}$

Hope this helps you.

Let me know if you have any other questions :-):-)

6 0

3 years ago

Read 2 more answers

(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How

OLEGan [10]

Answer:

(a) Current flowing through truck battery is 180 A

(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

The charge on the truck battery,q = 720 C

Time, t = 4.00 s

Consider I be the current flowing through truck battery.

The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

$I=\frac{720}{4}$

I = 180 A

(b) Given:

The charge on the calculator,q = 7.00 C

The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A

Consider t be the time.

The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

$t=\frac{1}{0.3\times10^{-3} }$

I = 333.33 s

8 0

4 years ago