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Lera25 [3.4K]
3 years ago
8

Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aque

ous solution of magnesium (II) chloride. What substance is being oxidized.'
Chemistry
1 answer:
Andrei [34K]3 years ago
5 0

Answer: Magnesium Mg

Explanation:

Oxidization is the process by which a substance either gains oxygen or losses electrons.

The chemical reaction of the above is denoted by,

Mg(s) + 2HCl(aq) -----> MgCl2(aq) + H2(g)

Mg went from a 0 to a +2 state which would mean that it lost electrons.

It was therefore oxidized.

Please do react or comment if you need clarification or if the answer helped you. This can help other users as well. Thank you.

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Propose a mechanism for the following reaction.
raketka [301]
First, recognize that this is an elimination reaction in which hydroxide must leave and a double bond must form in its place. It is likely an E2 reaction. Here is an efficient mechanism:
1) Pre-reaction: Protonate the -OH to make it a good leaving group, water. H2SO4 or any strong H+ donor works. The water is positively charged but still connected to the compound.
2) E2: Use a sterically hindered base, such as tert-butoxide (tButO-) to abstract the hydrogen from the secondary carbon. [You want a sterically hindered base because a strong, non-sterically hindered base could also abstract a hydrogen from one of the two methyl groups on the tertiary carbon, and that leads to unwanted products, which is not efficient]. As the proton of hydrogen is abstracted, water leaves at the same time, creating an intermediate tertiary carbocation, and the 2 electrons in the C-H bond immediately are used to make a double bond towards the partial positive charge.
In the products we see the major product and water, as expected. Even though you have an intermediate, remember that an E2 mechanism technically happens in one step after -OH protonation. 
5 0
3 years ago
What is the major organic product obtained from the following reaction?
trapecia [35]

The correct option is (b)

NaNH2 is an effective base. It can be a good nucleophile in the few situations where its strong basicity does not have negative side effects. It is employed in elimination reactions as well as the deprotonation of weak acids.Alkynes, alcohols, and a variety of other functional groups with acidic protons, such as esters and ketones, will all be deprotonated by NaNH2, a powerful base.Alkynes are deprotonated with NaNH2 to produce what are known as "acetylide" ions. These ions are powerful nucleophiles that can react with alkyl halides to create carbon-carbon bonds and add to carbonyls in an addition reaction.Acid/base and nucleophilic substitution are the two types of reactions.Using the right base, terminal alkynes can be deprotonated to produce a carbanion.A good C is the acetylide carbanion.The acetylide carbanion can undergo nucleophilic substitution reactions because it is a potent C nucleophile. (often SN2) with 1 or 2 alkyl halides with electrophilic C to create an internal alkyne (Cl, Br, or I).Elimination is more likely to occur with 3-alkyl halides.It is possible to swap either one or both of the terminal H atoms in ethylene (acetylene) to create monosubstituted (R-C-C-H) and symmetrical (R = R') or unsymmetrical (R not equal to R') disubstituted alkynes (R-C-C-R').

Learn more about NANH2 here :-

brainly.com/question/12601787

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7 0
2 years ago
The gaseous product of a reaction is collected in a 25.0L container at 27.0 C. The pressure in the container is 3.0atm and the g
NeX [460]

Answer: The molar mass of the gas is 31.6 g/mol

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 3.0 atm

V = Volume of gas = 25.0 L

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =27.0^0C=(27.0+273)K=300K

n=\frac{PV}{RT}

n=\frac{3.0atm\times 25.0L}{0.0821 L atm/K mol\times 300K}=3.04moles

Moles =\frac{\text {given mass}}{\text {Molar mass}}

3.04=\frac{96.0g}{\text {Molar mass}}

{\text {Molar mass}}=31.6g/mol

The molar mass of the gas is 31.6 g/mol

4 0
3 years ago
7. An element's most stable ion forms an ionic compound with chlorine having the formula XCl2. If the ion of element X has a mas
Serhud [2]

Answer:

The element is strontium and the number of neutrons it have is 51.

Explanation:

Based on the given information, the ionic compound is,  

XCl₂ ⇔ X₂⁺ + 2Cl⁻

X2+ is the ion of the mentioned element

As mentioned in the given question, the number of electrons of the element X is 36 and as seen from the reaction the charge present on the ion is +2. Now the atomic number will be,  

No. of electrons = atomic number - charge

36 = atomic number - 2

Atomic number = 38

Based on the periodic table, the atomic number 38 is for strontium element, and the sign of strontium is Sr. Hence, the element X is Sr.  

Now based on the given information, the mass number of the element is 89. Now the no. of neutrons will be,  

No. of neutrons = mass number - atomic number

= 89 - 38

= 51 neutrons.  

4 0
3 years ago
Among K, Ca and Ba, which element possess low ionization energy?
deff fn [24]

Among the elements Barium has the lowest Ionization Energy.

<h3>What is Ionization Process ?</h3>

The process by which any neutral atom gets converted into electrically charged by gaining or losing electron is called Ionization Process.

K  is an alkali metal  it has to lose one electron to attain stable electronic configuration of an inert gas

For removing second electron , a stable configuration has to be broken and so will require high amount of energy.

Ca and Ba are alkaline earth metals.

They both have to lose 2 electrons to attain  stable electronic configuration of noble gas.

They have low Iow Ionization Energy as compared to K.

Ca has higher  Ionization Energy as compared to Ba because when we move down the periodic table , The ionization energy decreases.

Hence , Among the elements Barium has the lowest Ionization Energy.

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5 0
2 years ago
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