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Mrac [35]
3 years ago
5

How might a chef use chemistry?

Chemistry
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

A. Chemistry can help a chef understand how to combine different ingredients in a recipe.

Explanation:

Knowing the chemical reactions between ingredients used in cooking helps chefs understand how well different ingredients would react to eachother.

*Im pretty sure this is correct.

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Cole is working with radioactive particles and has set up a shield made of aluminum for protection. Which of the following will
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Answer:

C.) Alpha, beta, and gamma particles

Explanation:

A dense shield of aluminium can protect Cole from all the listed types of radiation produced from the radioactive particles.

A radioactive protector has very unique and specie ability to contain and prevent the movement of radiations of any types from going into the body.

The strongest and most penetrating radiations are the gamma rays. Any material that can prevent the movement of these rays can halt alpha and beta particles too.

An aluminium shield is made up of multiple layers of aluminium stacked together and it provides enough resistance.

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How many types of biodiversity Are there
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Species
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• We obtained the above 10.00-mL solution by diluting a stock solution using a 1.00-mL aliquot and placing it into a 25.00-mL vo
garik1379 [7]

Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) 0.0035 mole

c)  0.166 M

Explanation:

Phosphoric acid is tripotic because it has 3 acidic hydrogen atom surrounding it.

The equation of the reaction is expressed as:

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

1 mole         3 mole

The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b)  if 10.00 mL of a phosphoric acid solution required the addition of 17.50 mL of a 0.200 M NaOH(aq) to reach the endpoint; Then the molarity of the solution is calculated as follows

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

10 ml            17.50 ml

(x) M              0.200 M

Molarity = \frac{0.2*17.5}{1000}

= 0.0035 mole

c) What was the molar concentration of phosphoric acid in the original stock solution?

By stoichiometry, converting moles of NaOH to H₃PO₄; we have

= 0.0035 \ mole \ of NaOH* \frac{1 mole of H_3PO_4}{3 \ mole \ of \ NaOH}

= 0.00166 mole of H₃PO₄

Using the molarity equation to determine the molar concentration of phosphoric acid in the original stock solution; we have:

Molar Concentration =  \frac{mole \ \ of \ soulte }{ Volume \ of \ solution }

Molar Concentration = \frac{0.00166 \ mole \ of \  H_3PO_4 }{10}*1000

Molar Concentration = 0.166 M

∴  the molar concentration of phosphoric acid in the original stock solution = 0.166 M

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