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Julli [10]
3 years ago
8

Chemical evolution explains how living systems were created from

Chemistry
2 answers:
boyakko [2]3 years ago
8 0
Non-living molecules.
Hope it helps! :)
Olenka [21]3 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

When simple inorganic molecules are used to lead to the formation of complex organic molecules then it is known as chemical evolution.

Basically in a chemical evolution more stable molecules are formed from different small forms.

For example, formation of polymers take place when number of monomer units combine together.

Hence, we can conclude that chemical evolution explains how living systems were created from  non-living molecules.

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Sighting along the C2-C3 bond of 2-methylbutane, the least stable conformation (Newman projection) has a total energy strain of
natima [27]

Answer:

21 KJ/mol

Explanation:

For this question, we have to start with the <u>linear structure</u> of 2-methylbutane. With the linear structure, we can start to propose all the <u>Newman projections</u> keep it in mind that the point of view is between carbons 2 and 3 (see figure 1).

Additionally, we have several <u>energy values for each interaction</u> present in the Newman structures:

-) Methyl-methyl <em>gauche: 3.8 KJ/mol</em>

-) Methyl-H <em>eclipse: 6.0 KJ/mol</em>

-) Methyl-methyl <em>eclipse: 11.0 KJ/mol</em>

-) H-H <em>eclipse:</em> 4.0 KJ/mol

Now, we can calculate the energy for each molecule.

<u>Molecule A</u>

In this molecule, we have 2 Methyl-methyl <em>gauche </em>interactions only, so:

(3.8x2) = 7.6 KJ/mol

<u>Molecule B</u>

In this molecule, we have a Methyl-methyl <em>eclipse </em>interaction a Methyl-H <em>eclipse </em>interaction and an H-H <em>eclipse</em> interaction, so:

(11)+(6)+(4) = 21 KJ/mol

<u>Molecule C</u>

In this molecule, we have 1 Methyl-methyl <em>gauche </em>interaction only, so:

3.8 KJ/mol

<u>Molecule D</u>

In this molecule, we have three Methyl-H <em>eclipse </em>interaction, so:

(6*3) = 18 KJ/mol

<u>Molecule E</u>

In this molecule, we have 1 Methyl-methyl <em>gauche </em>interaction only, so:

3.8 KJ/mol

<u>Molecule F</u>

In this molecule, we have a Methyl-methyl <em>eclipse </em>interaction a Methyl-H <em>eclipse </em>interaction and an H-H <em>eclipse</em> interaction, so:

(11)+(6)+(4) = 21 KJ/mol

The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

I hope it helps!

3 0
4 years ago
what is the empirical formula of a compound that contains 15.77% aluminum, 28.11% sulfur and 56.12% oxygen
Marizza181 [45]
<h3>Answer:</h3>

Al₂(SO₄)₃

<h3>Explanation:</h3>

We are given percentage composition of elements in a compound;

  • Aluminium is 15.77%
  • Sulfur is 28.11 %
  • Oxygen is 56.12%

We are required to calculate the empirical formula of the compound.

  • Assuming the mass of the compound is 100 g then the masses of the elements is;

Aluminium = 15.77 g

Sulfur = 28.11

Oxygen = 56.12

We can determine the number of moles of each;

Moles of Aluminium = 15.77 g ÷ 26.98 g/mol

                                 = 0.585 moles

Moles of sulfur = 28.11 g ÷ 32.07 g/mol

                         = 0.877 moles

Moles of Oxygen = 56.12 g ÷ 16.0 g/mol

                            = 3.5075 moles

  • But, the empirical formula is the simplest whole number ratio of elements in a compound.
  • Therefore; we need to get the ratio of moles of the above elements;

Aluminium : Sulfur : Oxygen

0.585 mol  :  0.877 mol : 3.5075 mol

0.585/0.585 : 0.877/0.585 : 3.5075/0.585

    1 : 1.5 : 6

But, we need whole number ratios, therefore;

= (1 : 1.5 : 6 ) × 2

= 2 : 3 : 12

Therefore; the formula of the compound is Al₂S₃O₁₂

The compound is written as Al₂(SO₄)₃

Thus, the empirical formula of the compound is Al₂(SO₄)₃

3 0
3 years ago
Paki hanap nga po ng GRAVITY at POWER<br>Maraming Salamat po❤️<br><br>Sana matulungan niyo po ako​
MAXImum [283]

Please mark me as brainliest!

6 0
3 years ago
If the following elements were to form ions, what is the expectant charge?<br> Ca<br> Na<br> P
Ksju [112]
You can use the periodic table to help you determine the charge of an element when it becomes an ion. You base this on the group 8 elements called the noble gases. You can determine the charge by finding the difference of the atomic numbers of the given element to their nearest noble gas. It is made easier for elements on the left side. You can take their charge to be their group number. Since calcium is in group 2A, it will have a charge of 2+. Since Na is in group 1A, it will have a charge of 1+. Since Phosphorus is a nonmetal, it will have a negative charge because it needs to gain electrons to achieve their nearest noble gas. Since the nearest noble gas is Argon having an atomic number of 18, while Phosphorus has an atomic number of 15:

Charge = 15 - 18 = -3

The charge of Phosphorus is -3.
3 0
4 years ago
Read 2 more answers
S
ozzi

Answer:

For more information about each chemical, view the safety data sheets. Click the Product Resources tab followed by Datasheet. You’ll need these materials: test tube rack test tubes (quantity: 6) test tube labels graduated cylinder wash bottle with distilled water (Tap water is acceptable, but it can skew the experimental results.) pipettes (quantity: 2) forceps 50-milliliter Erlenmeyer ask scoop test tube brush apron goggles gloves pen or re-tip marker small piece of sandpaper chemicals from Edmentum Lab kit: copper metal strip (quantity: 1) iron nails (quantity: 2) zinc metal strips (quantity: 3) copper(II) sulfate solution (10 milliliters) iron(III) nitrate solution (10 milliliters), also called ferric nitrate magnesium sulfate solution (10 milliliters) hydrochloric acid (30 milliliters) sodium bicarbonate (7.5 grams

Hope this helps

Explanation:

3 0
3 years ago
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