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Blizzard [7]
3 years ago
10

How many valence electrons are in beryllium?

Chemistry
1 answer:
stellarik [79]3 years ago
7 0
There are 2 valence electrons
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When do replicated chromosomes are aligned in the center
Art [367]

Answer:

<u>During Metaphase</u>

<u></u>

Explanation:

During Metaphase the cell chromosome align themselves in the middle of the cell.This occur due to a cellular process called "Tug of War".

The chromosome which have been replicated and joined at the central point  called centromere are called sister chromatids

Prior to metaphase , Kinetochore type of protein are formed around the centromere. Long protein filament called kinetochore are extended from poles to other end of the cell attached to kinetochore.

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7 0
3 years ago
How many moles in 4.3 x 1024 atoms of sodium (Na)?
wel

Answer:How many ions are in 2 moles of NaCl?

2 mol NaCl = 2 x 6.02 x 10 23 = 1.204 x 10 24 NaCl formula units 2 mol NaCl = 2 (2 x 6.02 x 10 23 )= 2 (1.204 x 10 24) = 2.408 x 10 24 atoms *2 moles of sodium chloride contains 2.408 x 10 24 ions (combination of Na + ions & Cl – ions). H

Explanation:

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3 0
3 years ago
I need help 7th grade science
MrRissso [65]

Answer:

a flowing stream

Explanation:

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7 0
3 years ago
True or false - The electrostatic attraction of the nucleus and the outermost electron increases as you go down the group.
Mashutka [201]

Answer:

its true

Explanation:

3 0
2 years ago
A Beer's law plot for Cu2+ was experimentally obtained. The slope of the Beer's law plot was 310 L/mol (with a y-intercept = 0.0
algol [13]

Answer:

1.7742\times 10^{-3} mol/L is the molar concentration of Cu(II) ions in the unknown solution.

Explanation:

Using Beer-Lambert's law :

Formula used :

A=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution

l = length of the cell =

\epsilon = molar absorptivity of solution

A Beer's law plot is between absorbance and concentration.

\frac{A}{c}=Slope(m)=\epsilon\times l

We have:

A = 0.55

The slope of the Beer's law plot = m = 310 L/mol

So, the concentration of the solution is:

c=\frac{A}{m}=\frac{0.55}{310 L/mol}=1.7742\times 10^{-3} mol/L

1.7742\times 10^{-3} mol/L is the molar concentration of Cu(II) ions in the unknown solution.

8 0
3 years ago
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