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Answer:
The pH of the solution is 1.38.
Explanation:
Mass of HCl = 614 mg = 0.614 g
Moles of HCl = 
Concentration of HCl :

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.
![[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M](https://tex.z-dn.net/?f=%5BHCl%5D%3D%5Cfrac%7B0.01682%20mol%7D%7B0.4%20L%7D%3D0.04205%20M)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.
Then 0.04205 mol/L of HCl will give:
of hydronium ions.
![[H_3O^+]=0.04205 M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D0.04205%20M)
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![pH=-\log [0.04205 M]=1.38](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5B0.04205%20M%5D%3D1.38%20)
The pH of the solution is 1.38.
Answer:Chemical bonds form when the valence electrons of one atom interact with the valence electrons of another atom.J
Explanation: Byee stay safe: Wear your mask, drink water and stan bts
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Answer:
A) 4P + 5O₂ → 2P₂O₅
Explanation:
A) 4P + 5O₂ → 2P₂O₅
This equation is balanced. There are four phosphorus and ten oxygen atoms are on both side of equation.
B) 5P + 4O₂ → 2P₄O₅
This equation is not balanced. There are five phosphorus and eight oxygen atoms on left, eight phosphorus ten oxygen on right side of equation.
C) 2P + O₂ → P₂O₅
This equation is not balanced. There are two phosphorus, two oxygen atoms on left and two phosphorus five oxygen on right side of equation.
D) 4P + 2O₂ → 2P₄O₅
This equation is not balanced. There are four phosphorus, four oxygen atoms on left and eight phosphorus ten oxygen on right side of equation.
Answer : The fugacity in the solution is, 16 bar.
Explanation : Given,
Fugacity of a pure component = 40 bar
Mole fraction of component = 0.4
Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.
Now we have to calculate the fugacity in the solution.
Formula used :

where,
= fugacity in the solution
= fugacity of a pure component
= mole fraction of component
Now put all the give values in the above formula, we get:


Therefore, the fugacity in the solution is, 16 bar.