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Andru [333]
3 years ago
15

The monatomic ions of Groups 1A(1) and 7A(17) are all singly charged. In what major way do they differ? Why?

Chemistry
2 answers:
grin007 [14]3 years ago
8 0

Answer:

Group 1A forms single charged cations whereas group 7A forms singly charged anions

Explanation:

Charge of an atom is indicative of the number of electrons lost or gained by the atom. Cations are positively charged ions formed by the loss of electrons while anions are negatively charged ions formed by the gain of electrons.

In the periodic table Group 1A belongs to the alkali metals which have a valence electron configuration of ns¹ i.e they have one electron in their valence orbital. Since they are metals these elements lose electrons readily gaining a +1 charge and forming a singly charged cation.

Group 7A belongs to the halogens which have a valence electron configuration of ns² np⁵ i.e they have 7 electrons in their valence orbital. They only need one more electron to complete their octet and become stable. As a result halogens are highly electronegative and form singly charged anion (-1 charge).

insens350 [35]3 years ago
3 0

<u>Answer:</u> Group 1 ions are known as cations and Group 17 ions are known as anions.

<u>Explanation:</u>

Ions are formed when an atom looses or gains electrons.

If an atom gains electrons, it leads to the formation of negative ions known as anions. <u>For Example:</u> Fluorine is a Group 17 element which gains 1 electron to form F^- ions.

If an atom looses electrons, it leads to the formation of positive ions known as cations. <u>For Example:</u> Sodium is a Group 1 element which looses 1 electron to form Na^+ ions.

Hence, group 1 ions are known as cations and Group 17 ions are known as anions.

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Using the same sample of gas (P1 = 565 torr , T1 = 27 ∘C ), we wish to change the pressure to 5650 torr with no accompanying cha
Stels [109]

Answer:

2726.85 °C

Explanation:

Given data:

Initial pressure = 565 torr

Initial temperature = 27°C

Final temperature = ?

Final pressure = 5650 torr

Solution:

Initial temperature = 27°C (27+273 = 300 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

T₂  = P₂T₁ /P₁

T₂  = 5650 torr × 300 K / 565 torr

T₂  = 1695000 torr. K /565 torr

T₂ = 3000 K

Kelvin to degree Celsius:

3000 K - 273.15 = 2726.85 °C

4 0
2 years ago
A 15.00-ml sample of a naoh solution of unknown concentration requires 17.88 ml of a 0.1053 m h2so4 solution to reach the equiva
Sergeu [11.5K]

Answer:

  • <u>0.1255 M</u>

Explanation:

<u>1) Data:</u>

Base: NaOH

Vb = 15.00 ml = 15.00 / 1,000 liter

Mb = ?

Acid: H₂SO₄

Va = 17.88 ml = 17.88 / 1,000 liter

Ma = 0.1053

<u>2) Chemical reaction:</u>

The <em>titration</em> is an acid-base (neutralization) reaction to yield a salt and water:

  • Acid + Base → Salt + Water

  • H₂SO₄ (aq) + NaOH(aq) → Na₂SO₄ (aq) + H₂O (l)

<u>3) Balanced chemical equation:</u>

  • H₂SO₄ (aq) + 2 NaOH(aq) → Na₂SO₄ (aq) + 2H₂O (l)

Placing coefficient 2 in front of NaOH and H₂O balances the equation

<u>4) Stoichiometric mole ratio:</u>

The coefficients of the balanced chemical equation show that 1 mole of H₂SO₄ react with 2 moles of NaOH. Hence, the mole ratio is:

  • 1 mole H₂SO₄ : 2 mole NaOH

<u>5) Calculations:</u>

a) Molarity formula: M = n / V (in liter)

   ⇒ n = M × V

b) Nunber of moles of acid:

  • nₐ = Ma × Va = 0.1053 (17.88 / 1,000)

c) Number of moles of base, nb:

  • nb = Mb × Vb = Mb × (15.00 / 1,000)

d) At equivalence point number of moles of acid = number of moles of base

  • nₐ = nb

  • 0.1053 × (17.88 / 1,000) =  Mb × (15.00 / 1,000)

  • Mb = 0.1053 × 17.88  / 15.00 = 0.1255 mole/liter = 0.1255 M
3 0
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3 0
3 years ago
= 25 X 5 = (use the correct number of sig figs)
Anton [14]

Answer:

1.25 *10^2

Explanation:

25*5 = 125

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5 0
3 years ago
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