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Dovator [93]
3 years ago
5

martin climbs 3 1/3 meters in the first 1/6 hour alexia climbs 17 1/2 meters in the first 5/6hour what is the rate martin and al

exia climbed show workkk
Mathematics
1 answer:
Yuri [45]3 years ago
7 0
Rate is given by:
rate=(distance )/(time)
Martin's rate will be:
(3 1/3)/(1/6)
=(10/3)/(1/6)
=20 meters per hour

Alexia's rate is:
(17 1/2)/(5/6)
=(35/2)/(5/6)
=21 meters per hour
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The angle measures associated with which set of ordered pairs share the same reference angle? (Negative StartFraction StartRoot
Katarina [22]

Answer:

(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

5 0
3 years ago
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What is the value of x?
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Answer:

Step-by-step explanation:

10

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3 years ago
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A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th
morpeh [17]
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
6 0
3 years ago
What is the x-value in the solution to this system of linear equations? 2x − y = 11 x + 3y = −5
Setler [38]

Answer:

x = 4

Step-by-step explanation:

Given the 2 equations

2x - y = 11 → (1)

x + 3y = - 5 → (2)

Multiply (1) by 3 and add to (2) to eliminate the y- term

6x - 3y = 33 → (3)

Add (2) and (3) term by term to eliminate y, that is

7x = 28 ( divide both sides by 7 )

x = 4

4 0
3 years ago
Pls help I’m failing
lara [203]

Answer:

a.

the area of each parallelogram

<em>a. 66</em>

<em>b. 49</em>

<em>c. 25</em>

<em>d. 32</em>

<em>e. 18</em>

Step-by-step explanation:

a parallelogram is similar to a rectangle when you are finding the ares, you use the base and the height to find the area. If it helps, like the text suggested, just change them to look like a rectangle and then find the area.

8 0
3 years ago
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