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777dan777 [17]
3 years ago
11

Relate dark matter to the development of the universe after the Big Bang. In 3-5 sentences, speculate on how the development of

the universe would have been different if there had been no dark matter. In your answer, use the term structures.
Please answer
Chemistry
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

Dark matter makes up 85% of the mass of the universe. Dark matter is not directly observable because it doesn't interact with any electromagnetic wave. In the development of the universe, without dark matter, the universe will not function, move or rotate as it does now (this speculation led to the quest to find the anomaly of mass and energy in the known universe, eventually leading to the idealization of dark matter) and will not have enough gravitational force to hold it together.  After the big bang,<em> the presence of dark matter and energy ensured that the newly formed universe didn't just float away, rather, it provided enough gravitational force to hold the universe while still allowing it to expand sufficiently</em>.

The development of the universe would have been different without the universe in the sense that the young universe won't have enough mass to hold it together, and the universe would have simply floated apart. The behavior of the universe would have been different from what we observe now, and some physical laws that applies now will not apply to the universe.

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If you have access to stock solutions of 1.00 M H3PO4, 1.00 M of HCl, and 1.00 M NaOH solution, (and distilled water of course),
garri49 [273]

Answer:

0.10L of 1.00M of H₃PO₄ and 0.1613L of 1.00M NaOH

Explanation:

The pKa's of phosphoric acid are:

H₃PO₄/H₂PO₄⁻ = 2.1

H₂PO₄⁻/HPO₄²⁻ = 7.2

HPO₄²⁻/PO₄³⁻ = 12.0

To make a buffer with pH 9.40 we need to convert all H₃PO₄ to H₂PO₄⁻ and an amount of H₂PO₄⁻ to HPO₄²⁻

To have a 50mM solution of phosphoures we need:

2L * (0.050mol / L) = 0.10 moles of H₃PO₄

0.10 mol * (1L / mol) = 0.10L of 1.00M of H3PO4

To convert the H₃PO₄ to H₂PO₄⁻ and to HPO₄²⁻ must be added NaOH, thus:

H₃PO₄ + NaOH → H₂PO₄⁻ + H₂O + Na⁺

H₂PO₄⁻ + NaOH → HPO₄²⁻ + H₂O + Na⁺

Using H-H equation we can find the amount of NaOH added:

pH = pKa + log [A⁻] / [HA] <em>(1)</em>

<em>Where [A-] is conjugate base, HPO₄²⁻ and [HA] is weak acid, H₂PO₄⁻</em>

<em>pH = 7.40</em>

<em>pKa = 7.20</em>

[A-] + [HA] = 0.10moles <em>(2)</em>

Replacing (2) in (1):

7.40 = 7.20 + log 0.10mol - [HA] / [HA]

0.2 = log 0.10mol - [HA] / [HA]

1.5849 = 0.10mol - [HA] / [HA]

1.5849 [HA] = 0.10mol - [HA]

2.5849[HA] = 0.10mol

[HA] = 0.0387 moles = H₂PO₄⁻ moles

That means moles of HPO₄²⁻ are 0.10mol - 0.0387moles = 0.0613 moles

The moles of NaOH needed to convert all H₃PO₄ in H₂PO₄⁻ are 0.10 moles

And moles needed to obtain 0.0613 moles of HPO₄²⁻ are 0.0613 moles

Total moles of NaOH are 0.1613moles * (1L / 1mol) = 0.1613L of 1.00M NaOH

Then, you need to dilute both solutions to 2.00L with distilled water.

4 0
2 years ago
Why is the periodic table such a brilliant piece of work? Explain and give two reasons.​
Aleksandr-060686 [28]

Answer:

Because it keeps track of all the elements

6 0
3 years ago
Write a reflection about your learning in this unit. Your reflection should be at least 3 sentences. Use the following sentence
Vera_Pavlovna [14]

Answer:

This unit has encouraged a deeper understanding of the world and it's guiding principles. While it was initially challenging for me to determine if a change was physical or chemical, this unit provided me with the information necessary to determine the type. With this knowledge, I can now interrelate with other properties and believe that this new ability will assist in future units as well. Thank you!

Explanation:

5 0
1 year ago
Which of the following compounds will be most soluble in ethanol (CH3CH2OH)?hexane (CH3CH2CH2CH2CH2CH3)ethylene glycol (HOCH2CH2
jonny [76]

Answer:

Ethylene glycol

Explanation:

Solubility results when there is some kind of interaction between the solute and its solvent. In the case of ethylene glycol, it could form intermolecular hydrogen bonds with ethanol and is hence miscible with ethanol in all proportions.

6 0
3 years ago
An aqueous magnesium chloride solution is made by dissolving 6.92 6.92 moles of MgCl 2 MgCl2 in sufficient water so that the fin
Naddika [18.5K]

Answer:

[MgCl₂] = 0.036 M

Explanation:

Molarity are the moles of solute in 1L of solution.

For this case, our solution's volume is 2L

First of all, we convert the mass of solute (MgCl₂) to moles

6.92 g . 1mol / 95.2 g = 0.0727 moles

Now, we make a rule of three:

In 2L of solution we have 0.0727 moles of solute

Then, in 1L of solution we may have, 1L . 0.0727 mol / 2L = 0.036 M

3 0
3 years ago
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