Calculate the density of helium if a balloon with a capacity of 5.00 L holds 0.890 g.

Chemistry

1 answer:

liubo4ka [24]2 years ago

5 0

Answer:

Explanation:

Density is m/V. Also, 1 liter = 1000 $cm^3$ . So, we get 0.890/(5*1000) = $1.78*10^{-4}$ g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.

You might be interested in

A sample of sugar (C12H22O11) contains

Oduvanchick [21]

Answer: 0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N = number of particles

Nᵃ = Avogadros constant = 6.02 x

So, n=

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

5 0

2 years ago

Which of the following transports information from the eye to the brain?

Marina CMI [18]

Answer:

Explanation:

c is the correct answer

4 0

2 years ago

For which of the following activities might you want to hire a chemist?

Basile [38]

Answer:

OPTION (A) : Testing a rock sample for gold content

Explanation:

For testing a rock sample of gold content you will need a Chemist. To test the material, the sample is rubbed on black stone which will leave a mark on the stone. This mark is tested by applying aqua fortis i.e nitric acid on the mark. If the mark gets dissolve then the material is not gold. If the mark sustain the it is further tested by applying aqua regia i.e nitric acid and hydrochloric acid which will prove the sample is of gold if it gets dissolve on using hydrochloric acid. The purity of the sample can be checked by differing the concentration of the aqua regia and comparing it with the gold material of the known purity.