The brackets used to express concentration [ ], when making equilibrium constant calculations, indicate

1 answer:

4 0

Constant is K and that is the the concentration of product over the concentration of reactant for example for the equlibrium equation below
A+2B=3C
K= [C]^3/( [A]* [B]^2

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CHEM HELP!

sweet [91]

So let's convert this amount of mL to grams:

$\frac{13.6g}{1mL}*1.2mL=16.32g$

Then we need to convert to moles using the molar weight found on the periodic table for mercury (Hg):

$\frac{1mole}{200.59g}*16.32g=8.135*10^{-2}mol$

Then we need to convert moles to atoms using Avogadro's number:

$\frac{6.022*10^{23}atoms}{1mole} *[8.135*10^{-2}mol]=4.90*10^{22}atoms$

So now we know that in 1.2 mL of liquid mercury, there are $4.90*10^{22}atoms$ present.

4 0

4 years ago

? What is the oxidation number of B in HBO3? D-1 0 O +3 O +6

lesya692 [45]

H20* SOO N34 Thats my answer

6 0

3 years ago

The AP Biology teacher is measuring out 638.0 g of dextrose (C6H12O6) for a lab. How many moles of dextrose is this equivalent t

Katena32 [7]

The AP Biology teacher is measuring out 638.0 g of dextrose (C6H12O6) for a lab the moles of dextrose is this equivalent to is 3.6888 moles.

<h3>What are moles?</h3>

A mole is described as 6.02214076 × 1023 of a few chemical unit, be it atoms, molecules, ions, or others. The mole is a handy unit to apply due to the tremendous variety of atoms, molecules, or others in any substance.

To calculate molar equivalents for every reagent, divide the moles of that reagent through the moles of the restricting reagent. The calculation is follows:

655/12 x 6 + 12+ 16 x 6
= 655/ 180 = 3.6888 moles.