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tresset_1 [31]
4 years ago
8

The moon cannot be seen during which phase?

Chemistry
2 answers:
ycow [4]4 years ago
8 0
New moon is the phase in which it cannot be seen
Andrews [41]4 years ago
3 0
New Moon. The Moon's unilluminated side is facing the Earth. The Moon is not visible except during a solar eclipse. The lighted side of the Moon faces away from the Earth. This means that the Sun, Earth, and Moon are almost in a straight line, with the Moon in between the Sun and the Earth.
You might be interested in
Which of the following is a basic solution? HCl dissolved in water b. household ammonia c. vinegar d. pure water
PSYCHO15rus [73]

Answer:

B. Household ammonia.

Explanation:

NH₃ is a base, so the solution always will be basic.

NH₃ takes the proton from the water. In conclusion we have free OH⁻ in medium, that's why the solution is basic.

NH₃ + H₂O → NH₄⁺  +  OH⁻

- HCl + H₂O → H₃O⁺  + Cl⁻

This reaction makes an acid solution, cause the H₃O⁺

- Vinegar is a compound made of acetic acid.

CH₃COOH  + H₂O  ⇄  H₃O⁺  +  CH₃COO⁻

This reaction also makes an acid solution, cause the H₃O⁺

- Pure water makes neutral solution. It is not acid, neither basic.

2H₂O ⇄  H₃O⁺  +  OH⁻

7 0
3 years ago
What conditions make G always positive?
Bess [88]
The answer is c ......
8 0
3 years ago
Read 2 more answers
Which substance has a mass is 13.5 grams, and its volume is 5 cm 3.
solmaris [256]

Answer:

Substance is Aluminium

Explanation:

We are given;

Mass; m = 13.5 grams

Volume; V = 5 cm³

Formula for density is;

density = m/V

Density = 13.5/5

Density = 2.7 g/cm³

From the table attached, we can see that the element with a corresponding density of 2.7 is Aluminium

5 0
3 years ago
Two or more assistance
Goryan [66]
I believe it would be a compound.
4 0
3 years ago
How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2
NNADVOKAT [17]

Answer:

17 g Ba(NO₂)₂

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

4.5 × 10²² molecules Ba(NO₂)₂

<u>Step 2: Define conversion</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

<u>Step 3: Dimensional Analysis</u>

<u />4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )

= 17.1384 g Ba(NO₂)₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂

7 0
3 years ago
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