Answer:
xcvbn
Explanation:
nkj
what he said
Answer:38°
NaOH > Na3PO4 > NaNO3
in NaOH
23/40 * 100 = 57.5%
in Na3PO4
3 * 23/164 * 100 = 42%
In NaNO3
23/85 * 100 = 27.1%
Hence;
Rn] 5f14 6d4 7s2 mp: none d: none. Seaborgium ..... Element. Density. Boiling or Melting Point in °C. Electron Configuration. Symbol.
Answer:just for the ponits
Explanation:ima be a jenna
