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Nataly [62]
3 years ago
15

Small cubes that are 10 cm on a side and larger ones that are 12 cm on a side are submerged in water. Cubes A and B are made of

steel (rho = 7 g/cm3) while cubes C and D are made of aluminum (rho = 2.7 g/cm3). Rank the buoyant force exerted in the cubes by the water from greatest to least.
Physics
1 answer:
Digiron [165]3 years ago
8 0

Answer

given,

given,

small cube side = 10 cm

larger cube side = 12 cm

density of steel = 7 g/cm³

density of aluminium = 2.7 g/cm³

density of the water (ρ₁)= 1 g/cm³

Cube A and B made of steel

buoyant force of Cube A

 B₁ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube B

 B₂ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force of Cube C

 B₃ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube D

 B₄ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force acting on the cube depends on the density of the fluid

hence,

B₂ = B₄  > B₁ = B₃

 

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Xelga [282]

To solve this problem we will apply the concepts related to the balance of forces. Said balance will be given between buoyancy force and weight, both described as derived from Newton's second law, are given as

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Here,

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\text{Weight of the sphere} = W = 0.34 N

\text{Volume} = V = 13 cm^3 = 13*10^{-6}m^3

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The total power delivered by the battery if the lightbulbs are connected is 9V^2/R

<h3>Power of a battery</h3>

The formula for calculating the power of a battery is expressed according to the equation;

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