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Nataly [62]
3 years ago
15

Small cubes that are 10 cm on a side and larger ones that are 12 cm on a side are submerged in water. Cubes A and B are made of

steel (rho = 7 g/cm3) while cubes C and D are made of aluminum (rho = 2.7 g/cm3). Rank the buoyant force exerted in the cubes by the water from greatest to least.
Physics
1 answer:
Digiron [165]3 years ago
8 0

Answer

given,

given,

small cube side = 10 cm

larger cube side = 12 cm

density of steel = 7 g/cm³

density of aluminium = 2.7 g/cm³

density of the water (ρ₁)= 1 g/cm³

Cube A and B made of steel

buoyant force of Cube A

 B₁ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube B

 B₂ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force of Cube C

 B₃ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube D

 B₄ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force acting on the cube depends on the density of the fluid

hence,

B₂ = B₄  > B₁ = B₃

 

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