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Nataly [62]
3 years ago
15

Small cubes that are 10 cm on a side and larger ones that are 12 cm on a side are submerged in water. Cubes A and B are made of

steel (rho = 7 g/cm3) while cubes C and D are made of aluminum (rho = 2.7 g/cm3). Rank the buoyant force exerted in the cubes by the water from greatest to least.
Physics
1 answer:
Digiron [165]3 years ago
8 0

Answer

given,

given,

small cube side = 10 cm

larger cube side = 12 cm

density of steel = 7 g/cm³

density of aluminium = 2.7 g/cm³

density of the water (ρ₁)= 1 g/cm³

Cube A and B made of steel

buoyant force of Cube A

 B₁ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube B

 B₂ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force of Cube C

 B₃ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube D

 B₄ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force acting on the cube depends on the density of the fluid

hence,

B₂ = B₄  > B₁ = B₃

 

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a car that is moving in a straight line has an acceleration of 8.0 m/s/s for 4.0 seconds. which one of the following is true of
Nuetrik [128]

Answer:

32 ms

Explanation:

v=32ms.

Explanation:

I will assume that you mean that the acceleration is 8.0 ms2, as 8.0ms is a value for velocity, not acceleration.

Here, we use the formula v=u+at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is time. Let's substitute values, then:

v=u+at,

v=0+8.0⋅4.0

v=32,

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Hope it Helps! :D .

7 0
2 years ago
Two people are standing on a 3.12-m-long platform, one at each end. The platform floats parallel to the ground on a cushion of a
Ann [662]

Answer:

The magnitude of displacement is 0.082m

Explanation:

While the ball is in motion,we have MV + mv= 0 ...eq1

Where M = combined mass of the platform and the two people.

V = velocity of the platform

m = mass of the ball

v = velocity of the ball

The distance that the platform moves is given by:

X = Vt ...eq2

Where t is the time that the ball is in the air.

The time the ball is in the air is given by:

L/(v-V) ...eq3

Where L is the length of the platform

The quantity(v-V) = velocity of the ball relative to the platform.

Combining eq2 and eq3

X = (V/(v - V))L

From eq1 , the ratios of the velocities is V/v = -m/M

X = (V/v)L / (1 - (V/v) = (-m/M) L /(1+ (m/M))

X = -mL/(M + m)

X = - (3.36kg × 3.12m) /( 119kg + 3.36kg)

X = - 10.48/ 122.36

X = -0.082m

The minus sign implies that the displacement of the platform is in the opposite direction to the displacement of the ball.

Therefore, the distance moved by the platform is the magnitude of this displacement 0.082m.

7 0
3 years ago
Read 2 more answers
Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the
Doss [256]

Answer:

v_{su} = 19.44 m/s

Explanation:

m_{su}=5.68x10^{29}kg\\m_{sa}=5.68x10^{26}kg

T=9.29x10^8\\r_{o}=1.43x10^{12}

If the sun considered as x=0 on the axis to put the center of the mass as a:

m_{su}*r_{o}=(m_{sa}+m_{su})*r_{1}

solve to r1

r_1=\frac{m_{sa}*r_{o}}{m_{sa}+m_{su}}=\frac{5.68x10^{26}*1.43x10^{12}}{5.68x10^{26}+5.68x10^{26}}

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Since

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v_{su}=\frac{m_{sa}*2*pi*(2r_{o}*r_{1}-r_{1}^2)}{T*m_{sa}*r_1}

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Anni [7]

Answer:

D

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