If a special type of ice has a specific heat capacity of 2060 J/kg K. How
1 answer:
Answer:
Q = 144612 Joules.
Explanation:
Given the following data;
Mass = 2.6 kg
Initial temperature = -27°C to Kelvin = 273 + (-27) = 246K
Final temperature = 0°C to Kelvin = 273K
Specific heat capacity = 2060 J/kgK.
To find the quantity of heat absorbed;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 273 - 246
dt = 27 K
Substituting the values into the equation, we have;
Q = 144612 Joules.
You might be interested in
Answer:
a) -113 N/C
b) -423.71 V
Explanation:
The Step by step explanation and solution has been attached in the attachment section.
Answer:
B. The truck and mosquito exert the same size force on each other.
Explanation:
Newton's third law (law of action-reaction) states that
"When an object A exerts a force (action) on an object B, then object B exerts an equal and opposite force (reaction) on object A"
In this case, we can call
object A = the truck
object B = the mosquito
Thereforce according to Newton's third law, the force exerted by the truck on the mosquito is equal in magnitude to the force exerted by the mosquito on the truck (and in opposite direction).
The reason for which the mosquito will experience much more damage is the fact that the mosquito's mass is much smaller than the truck's mass, and since the acceleration is inversely proportional to the mass:
the mosquito will experience a much larger deceleration than the truck, therefore much more damage.