If a special type of ice has a specific heat capacity of 2060 J/kg K. How
1 answer:
Answer:
Q = 144612 Joules.
Explanation:
Given the following data;
Mass = 2.6 kg
Initial temperature = -27°C to Kelvin = 273 + (-27) = 246K
Final temperature = 0°C to Kelvin = 273K
Specific heat capacity = 2060 J/kgK.
To find the quantity of heat absorbed;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 273 - 246
dt = 27 K
Substituting the values into the equation, we have;
Q = 144612 Joules.
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a ) It takes 4056.15 seconds ( 1 hour 7 minutes and 36 seconds ) to cross the river.
b ) 0.91 · 3000 = 2730 m
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a ) It takes 4056.15 seconds ( 1 hour 7 minutes and 36 seconds ) to cross the river.
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To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:
= Coulomb's constant
q = Charge
r = Radius
At the same time
The values of variables are the same, then if we replace in a single equation we have this expression,
If we replace the values, we have finally that the charge is,
Therefore the potential energy of the system is