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sasho [114]
3 years ago
15

If a special type of ice has a specific heat capacity of 2060 J/kg K. How

Physics
1 answer:
KengaRu [80]3 years ago
4 0

Answer:

Q = 144612 Joules.

Explanation:

Given the following data;

Mass = 2.6 kg

Initial temperature = -27°C to Kelvin = 273 + (-27) = 246K

Final temperature = 0°C to Kelvin = 273K

Specific heat capacity = 2060 J/kgK.

To find the quantity of heat absorbed;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 273 - 246

dt = 27 K

Substituting the values into the equation, we have;

Q = 2.6*2060*27

Q = 144612 Joules.

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The Earth's electric field creates a potential that increases 100 V for every meter of altitude. If an object of charge 4.5 mC a
castortr0y [4]

Answer:

The final kinetic energy is  K =  1.1 \ J

Explanation:

From the question we are told that

    The electric field is  E =  100 \ V/m

    The charge on the object is  q =  4.5 mC  =  4.5 *10^{-3} \ C

    The mass of the object is  m_o  =  68 \ g  = 0.68 \ kg

     The distance moved by the object is d =  1.0 \ m

The workdone on the object by the fields  is  mathematically represented as

   W =  [qE + mg]d

Now this workdone is equivalent to the final kinetic energy so  

      K = W =  [qE + mg]d

substituting values

        K = W =  [4.5*10^{-3  } *100  + 0.68 * 9.8]* 1

        K =  1.1 \ J

8 0
3 years ago
A mechanic has a wrench where the hand grip is 0.40 m from the axis of the bolt. To apply a torque of 170 N m with this wrench w
Grace [21]

Answer:

4.3 * 10 N

Explanation:

To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.

torque  = distance from pivot *  perpendicular force

170 Nm= 0.4 m * F

F = 425 N = 4.3 * 10 N rounded off to two significant figures

4 0
3 years ago
A 150kg person stands on a compression spring with spring constant 10000n/m and nominal length of 0.50.what is the total length
Ivahew [28]

Answer:

<em>The total length of the spring would be 0.65 m</em>

Explanation:

The Concept

Hooke's law evaluates the increment of  spring in relation to the force acting on the body. Hooke's law states that for a spring undergoing deformation, the  force applied is directly proportional to the deformation experienced by the spring. Hooke's law is represented thus;

F = k x ..................1

where F is the force applied to the spring

k is the spring constant

x is the spring stretch or extension

Step by Step Calculations

We have to obtain x before adding it to the nominal length, We make x the subject formula in equation 1;

x = F/k

but F = m x g

so, x = (m x g)/k

given that, the mass of the person m =150 kg

g is the acceleration due to gravity = 9.81 m/s^{2}

k is the spring constant = 10000 N/m

then x = (9.81 m/s^{2} x 150 kg)/10000 N/m

x = 0.14715 m

the extension experienced by the spring after the compression is 0.14715 m

The total length of the spring would be;

L = 0.14715 m + 0.5 m = 0.64715

L ≈  0.65 m

Therefore the total length of the spring would be 0.65 m

4 0
3 years ago
Help i forgot to complete this worksheet
Naily [24]

just search up the answer/ definition to all of them, rephrase into own words, then do the same for examples.

6 0
4 years ago
A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Anoth
Karo-lina-s [1.5K]

Answer:

8.467 gm

Explanation:

The law governing this problem is "The Law of Constant Composition "

As per this law, all compounds irrespective of their origin and source have the same composition and properties  in their purest form

It is a simple proportion and ratio related problem.

1.50 grams of carbon require 2.0 grams of oxygen

1.0 grams of carbon will require oxygen

=\frac{2}{1.5}

6.35 grams of carbon will require oxygen

\frac{2}{1.5}\times6.35= 8.4666\\= 8.467

6 0
3 years ago
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