4 years ago

At what width does a totality of a Solar Eclipse span?

Physics

1 answer:

kari74 [83]4 years ago

6 0

115km (71 miles) , the eclipse will also have a magnitude of 1.0306

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What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.

iren [92.7K]

Answer:

B. 34.78 m/s

Explanation:

Momentum of a body or an object is given as the product of its velocity and its mass.

Therefore;

Momentum= velocity x mass

But; velocity = ? mass =115 kg , momentum = 4,000 kgm/s

Thus; velocity= momentum/mass

= 4,000/115

= 34.78 m/s

6 0

3 years ago

Light is shining in the images. Which object reflects a lot of light, absorbs a little light, and transmits almost no light?

SVEN [57.7K]

I believe it is B, the object that reflects a lot of light, absorbs a little light, and transmit almost no light.

6 0

3 years ago

Read 2 more answers

Equals distance divided by time. speed distance time O acceleration

zloy xaker [14]

Answer:

<h2> $speed$ </h2>

Explanation:

Rule:

<h3>Speed= Distance/ Time</h3>

Hope this helps!

7 0

3 years ago

A 48.5 kg student runs down the sidewalk and jumps with a horizontal speed of 4.25 m/s onto a stationary skateboard. The student

storchak [24]

Answer:

2.39 kg

Explanation:

There is conservation of momentum here in this problem so we will use the following problem:

$m_1u_1+m_2u_2=(m_1+m_2)v$

where the mass of the student $m_1$ is 48.5 kg,

the mass of the skateboard $m_2$ is $m_2$ kg,

the initial speed of the student $u_1$ is 4.25 m/s; and

the speed of the student and skateboard $v$ is 4.05 m/s.

So substituting the given values in the above formula to get:

$(48.5*4.25) + (m_2 * 0) = (48.5 + m_2 ) * 4.05$

$206.125=196.425+4.05m_2$

$206.125 - 196.425 = 4.05m_2$

$m_2=\frac{9.7}{4.05}$

$m_2=2.39$

Therefore, the mass of the skateboard is 2.39 kg.

7 0

3 years ago

What is the momentum of an object with 9.74 kg and 15 m/s?

dolphi86 [110]

Answer: 146.1 kg/m/s

Explanation: Momentum is equal to mass times velocity, so you do 9.74 kg times 15 m/s and get 146.1 kg/m/s.

6 0

3 years ago