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jonny [76]
2 years ago
9

What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second?

Physics
1 answer:
Alexus [3.1K]2 years ago
6 0

Given:-

  • Mass of the cart (m) = 35 kg
  • Speed (consider Velocity) = 1.2 m/s

To Find: Momentum of the cart.

We know,

p = mv

where,

  • p = Momentum,
  • m = Mass &
  • v = Velocity.

Thus,

p = (35 kg)(1.2 m/s)

→ p = 42 kg m/s (Ans.)

Conclusion:-

A. ☑️ 42 kilogram - metre per second.

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Sound waves are mechanical waves. Which statement is true for this type of wave?
Bad White [126]

Answer:

Electromagnetic waves do not require a medium in order to transport their energy. Mechanical waves are waves that require a medium in order to transport their energy from one location to another. ... Sound is a mechanical wave and cannot travel through a vacuum.

6 0
2 years ago
What is the numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall?
Nuetrik [128]

Answer:

9.8 m/s/s

Explanation:

The numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall is 9.8 m/s/s. This is called the acceleration due to gravity.

8 0
3 years ago
Read 2 more answers
Which component of a galaxy consists of tiny particles that look smoky or cloudy and
sladkih [1.3K]

Answer:

Cosmic dust

Explanation:

7 0
3 years ago
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Two positive point charges, each of which has a charge of 2.5 × 10−9 C, are located at y = + 0.50m and y = − 0.50m. Find the mag
nadya68 [22]

Answer:

F = 147,78*10⁻⁹ [N]

Explanation:

By symmetry the Fy components of the forces acting on charge in point x = 0,7 m canceled each other, and the total force will be twice Fx ( Fx is x axis component of one of the forces .

The angle β  ( angle between the line running through one of the charges in y axis and the charge in x axis) is

tan β  =  0,5/0,7

tan β  = 0,7142    then   β = arctan 0,7142      ⇒   β = 35 ⁰

cos  β = 0,81

d = √ (0,5)²  +  (0,7)²       d1stance between charges

d = √0,25 + 0,49

d =  √0,74  m

d = 0,86  m

Now Foce between two charges  is:

F  = K* q₁*q₂/ d²      (1)

Where  K  = 9*10⁹ N*m²/C²

q₁  =  2,5* 10⁻⁹C

q₂  = 3,0*10⁻⁹C

d²  = 0,74 m²

Plugging these values in (1)

F  =  9*10⁹* 2,5* 10⁻⁹*3,0*10⁻⁹ / 0,74       [N*m²/C²]*C*C/m²

F = 91,21 * 10⁻⁹   [N]

And  Fx  =  F*cos  β

Fx  =  91,21 * 10⁻⁹ *0,81

Fx =73,89*10⁻⁹  [N]

Then total force acting on charge located at x = 0,7 m is:

F = 2* Fx

F = 2*73,89*10⁻⁹  [N]

F = 147,78*10⁻⁹ [N]

8 0
3 years ago
A 30.0 kg box is placed on a 3.00 m tall shelf. What how much work was done on the box?
Kruka [31]

Answer:

W = 882.9[J]

Explanation:

In order to be able to calculate the work, we must first calculate the force necessary to lift the box. Since the necessary force is equivalent to the weight of the box, we can determine the weight of the box by means of the product of mass by gravitational acceleration.

w = m*g\\

where:

w = weight [N]

m = mass = 30 [kg]

g = gravity acceleration = 9.81 [m/s²]

w = 30*9.81\\w = 294.3 [N]

Now, the work can be calculated multiplying the force (weight) by the distance [m]

W = w*d\\W = 294.3*3\\W=882.9[J]

6 0
3 years ago
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