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3 years ago

Work is being done in which of these situations? all motions are at a constant velocity

Physics

1 answer:

fredd [130]3 years ago

7 0

Where the force is not perpendicular to the path of motion

are you missing the the situations ?

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The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou

Inessa05 [86]

Answer:

a) 4.40 s

b) 2.20 s

Explanation:

Given parameters are:

At constant power ,

initial speed of the car, $v_0=0$

final speed of the car, $v=32$ mph

At full power,

initial speed of the car, $v_0=0$

final speed of the car, $v=64$ mph

At constant power, $KE = \frac{1}{2} mv^2$

At full power, $KE = \frac{1}{2} m(2v)^2$

So $KE_f = 4KE_i$

So, time to reach 64 mph speed is 4 times more than the initial time

$t = 4*1.10 =4.40$ s

$v=v_0+at\\a=\frac{v-v_0}{t}=\frac{32-0}{1.1/3600}=104727.27$ $miles/hours^2$

For final 64 mph speed,

$v=v_0+at\\t=\frac{v-v_0}{a}=\frac{64-0}{104727.27} = 6.111*10^{-4}$ $hours$ = $6.111*10^{-4}*3600=2.20$ s

7 0

3 years ago

Maria makes a graphic organizer to compare open, closed, and short circuits. She adds the labels shown.

Lina20 [59]

The Answer is Label 1:Y Label 2: W

7 0

2 years ago

Read 2 more answers

Why did John Dalton describe atoms as solid spheres, and did he think all spheres were the same?

Ray Of Light [21]

Go here to get some help now a=can you help me i posted it on your profile

https://www.khanacademy.org/science/chemistry/electronic-structure-of-atoms/history-of-atomic-struct...

8 0

3 years ago

The feeling of being pushed into your seat when a car suddenly accelerates is an example of intertia

taurus [48]

Answer:

it is true

Explanation:

because the backward force you feel when your car accelerates is caused by your body's inertia

8 0

3 years ago

A counter attendant in a diner shoves a ketchup bottle with a mass 0.30 kg along a smooth, level lunch counter. The bottle leave

balu736 [363]

Answer:

1.176 N

Explanation:

$m$ = mass of the bottle = 0.30 kg

$v_{o}$ = initial speed of the bottle = 2.8 m/s

$v$ = final speed of the bottle = 0 m/s

$d$ = stopping distance traveled = 1.0 m

$f$ = magnitude of frictional force acting on bottle

Using work-change in kinetic energy theorem

$- f d = (0.5) m (v^{2} - v_{o}^{2} )\\- f (1) = (0.5) (0.30) (0^{2} - 2.8^{2} )\\-f = - 1.176 \\f = 1.176$ N

direction :

frictional force acts in opposite direction of motion.

8 0

3 years ago