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Setler [38]
3 years ago
7

The bottom of the hockey stick is called a?

Physics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

Blade Heel.

Explanation:

Brainliest please!!!

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A car moving in the positive direction with an initial velocity of 26 m/s slows down at a constant rate of -3 m/s2. What is its
Greeley [361]
The answer is 5 m/s
- 3 =  \frac{x - 26}{ 7}  \\ x =  \frac{7 \times(  - 3)}{1}  + 26 =  - 21 + 26 \\  = 5




good luck
8 0
3 years ago
A particle of mass 10 g and charge 72 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is
sineoko [7]

Answer:

-0.07163\hat k\ T or 0.07163 T into the page

Explanation:

m = Mass of particle = 10 g

a = Acceleration due to gravity = -9.8j m/s²

v = Velocity of particle = 19i km/s

q = Charge of particle = 72 μC

B = Magnetic field

Here the magnetic and gravitational forces on the particle are applied in the opposite direction so,

F_b=F_g

F_b=qvBsin\theta\\\Rightarrow F_b=qvBsin90\\\Rightarrow F_b=72\times 10^{-6}\times 19000B

F_g=ma\\\Rightarrow F_g=0.01\times -9.8

72\times 10^{-6}\times 19000B=0.01\times -9.8\\\Rightarrow B=\frac{0.01\times -9.8}{72\times 10^{-6}\times 19000}\\\Rightarrow B=-0.07163\hat k\ T

The magnetic field is 0.07163 T into the page

5 0
3 years ago
To understand the formula for power radiated in the form of electromagnetic energy by an object at nonzero temperature. every ob
lbvjy [14]

As per Stefan - Boltzmann law we know that

1. Power radiated in the form of electromagnetic energy by an object at nonzero temperature.

2. Every object at absolute (kelvin) temperature t will radiate electromagnetic waves.

3. This radiation is typically in the infrared for objects at room temperature, with some visible light emitted for objects heated above 1000 k.

4. The formula governing the rate of energy radiation from a surface is given by p=eσat^4,

where p is the thermal power (also known as the heat current h).

Thermal radiation in visible light can be seen on hot metalwork. Its emission in the infrared is invisible to the human eye. Infrared cameras are capable of capturing this infrared emission.

Thermal radiation is electromagnetic radiation generated by the thermal motion of charged particles in matter. All matter with a temperature greater than absolute zero emits thermal radiation. Particle motion results in charge-acceleration or dipole oscillation which produce electromagnetic radiation.

Examples of thermal radiation include the visible light and infrared light emitted by an incandescent light bulb, the infrared radiation emitted by animals that is detectable with an infrared camera, and the cosmic microwave background radiation. Thermal radiation is different from thermal convection and thermal conduction—a person near a raging bonfire feels radiant heating from the fire, even if the surrounding air is very cold.

Sunlight is part of thermal radiation generated by the hot plasma of the Sun. The Earth also emits thermal radiation, but at a much lower intensity and different spectral distribution. The Earth's absorption of solar radiation, followed by its outgoing thermal radiation, are the two most important processes that determine the temperature and climate of the Earth in most climate models.

So the correct answer which is applicable here will be

This formula applies to any object of total surface area a, kelvin temperature t, and emissivity e

here

\sigma[\tex] = stefan boltzmann constant = [tex]5.67 * 10^{-8}

3 0
3 years ago
A car accelerates uniformly from rest to speed 6.6 m/s in 6.5 s .Find the distance the car travel during this time .​
kirill [66]

Answer:

<em>The distance the car traveled is 21.45 m</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It occurs when an object changes its velocity at the same rate thus the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+at\qquad\qquad [1]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

Solving [1] for a:

\displaystyle a=\frac{v_f-v_o}{t}

Substituting the given data vo=0, vf=6.6 m/s, t=6.5 s:

\displaystyle a=\frac{6.6-0}{6.5}

a = 1.015\ m/s^2

The distance is now calculated with [2]:

\displaystyle x=0*6.5+\frac{1.015*6.5^2}{2}

x = 21.45 m

The distance the car traveled is 21.45 m

6 0
3 years ago
What do you notice from the picture?​
Schach [20]
Answer:there talking about the house
5 0
3 years ago
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