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GaryK [48]
2 years ago
10

Jf,fyu,eudyj,yudu.kjm,fj

Chemistry
2 answers:
dalvyx [7]2 years ago
8 0

Answer:

Yes that is correct

Explanation:

Si si yes yes

worty [1.4K]2 years ago
4 0

Answer:

Si, si, mi amigo

Explanation:

yes, yes, my friend

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What acid and base form Ca3(PO4)2
olya-2409 [2.1K]
Base is Ca(OH)2.
Acid is H3PO4.

First part of the salt comes from base, 
second par comes from the acid.
3 0
3 years ago
What is the name of this molecule?
Ludmilka [50]
Is there suppose to be a picture? Cause I do t see one
6 0
3 years ago
Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas.Express your a
ioda

Answer:

Explanation:

From the statement of the problem,

  B₂S₃_{s} + H₂O_{l}  →  H₃BO₃_{aq} + H₂S_{g}

              B₂S₃ + H₂O  →  H₃BO₃ + H₂S

We that the above expression does not conform with the law of conservation of mass:

To obey the law, we need to derive a balanced reaction equation:

   Let us use the mathematical method to obtain a balanced equation.

let the balanced equation be:

                        aB₂S₃ + bH₂O  →  cH₃BO₃ + dH₂S

where a, b, c and d will make the equation balanced.

  Conservating B: 2a = c

                          S: 3a = d

                          H: 2b = 3c + 2d

                           O: b = 3c

   if a = 1,

      c = 2,

      b = 6,

      2d = 2(6) - 3(2) = 6, d = 3

Now we can input this into our equation:

                     B₂S₃ + 6H₂O  →  2H₃BO₃ + 3H₂S

    B₂S₃_{s} + 6H₂O_{l}  →  2H₃BO₃_{aq} + 3H₂S_{g}

4 0
3 years ago
A student dissolves some solid NaNO3 in a beaker of water. Which are the solute and the solvent? Choose all answers that are cor
Paul [167]
The correct answer is D. The solute in this solution is the solid sodium nitrate (NaNO3) which is dissolved in the solvent, the water. Solute is the minor component in a solution whereas the solvent is the major component in the solution.
3 0
3 years ago
What is the mass of silver in 4.3g AgNO3?
gregori [183]
4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
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5 0
3 years ago
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