Question

(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of gas occupies 55 l under the conditions of the explosion, how many liters of gas are produced? (c) how many grams of n2 are produced in the detonation?

Answer 1

(2.09 mL) x (1.592 g/mL) / (227.0871 g C3H5O9N3/mol) = 0.014652 mole C3H5O9N 4 moles C3H5O9N produce 12 + 6 + 1 + 10 = 29 moles of gases, so: (0.014652 mole C3H5O9N) x (29/4) = 0.106 mole of gases (b) (0.106 mol) x (46 L/mol) = 4.88 L gases (c) (0.014652 mole C3H5O9N) x (6/4) x (28.0134 g/mol) = 0.616 g N2