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nlexa [21]
3 years ago
12

(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of

gas occupies 55 l under the conditions of the explosion, how many liters of gas are produced? (c) how many grams of n2 are produced in the detonation?
Chemistry
1 answer:
KATRIN_1 [288]3 years ago
3 0
<span>(2.09 mL) x (1.592 g/mL) / (227.0871 g C3H5O9N3/mol) = 0.014652 mole C3H5O9N 4 moles C3H5O9N produce 12 + 6 + 1 + 10 = 29 moles of gases, so: (0.014652 mole C3H5O9N) x (29/4) = 0.106 mole of gases (b) (0.106 mol) x (46 L/mol) = 4.88 L gases (c) (0.014652 mole C3H5O9N) x (6/4) x (28.0134 g/mol) = 0.616 g N2</span>
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2 years ago
What is bed rock made of
Darya [45]

Answer:

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8 0
3 years ago
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A sample of a substance that has a density of 0.824 g/mL has a mass of 0.451g. Calculate the volume of the sample.
Allushta [10]
Density can be calculated using the following rule:
density=mass/volume
therefore,
volume=mass/density

we have mass=0.451g and density=0.824g/ml
substituting in the above equation, we can calculate the volume as follows:
volume = 0.451/0.824 = 0.547 ml
8 0
4 years ago
Please I don’t get this at all someone help
ohaa [14]
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6 0
3 years ago
7. A 26.4-ml sample of ethylene gas, C2H4, has a pres-sure of 2.50 atm at 2.5°C. If the
never [62]

Answer: 1.87 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.50 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 26.4 ml

V_2 = final volume of gas = 36.2 ml

T_1 = initial temperature of gas = 2.5^oC=273+2.5=275.5K

T_2 = final temperature of gas = 10^oC=273+10=283K

Now put all the given values in the above equation, we get:

\frac{2.50\times 26.4}{275.5}=\frac{P_2\times 36.2}{283}

P_2=1.87atm

The new pressure is 1.87 atm by using combined gas law.

6 0
3 years ago
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