Answer:
a) -4 N
b) +4 N
Explanation:
Draw a free body diagram for each block.
For the large block, there are 2 forces: 12 N pushing to the right, and F pushing to the left.
For the small block, there is 1 force, F pushing to the right.
There are also weight and normal forces in the vertical direction, but we can ignore those.
Sum of forces on the large block in the x direction:
∑F = ma
12 − F = 4a
Sum of forces on the small block in the x direction:
∑F = ma
F = 2a
2F = 4a
Substitute:
12 − F = 2F
12 = 3F
F = 4
The small block pushes on the large block 4 N to the left (-4 N).
The large block pushes on the small block 4 N to the right (+4 N).
Answer:
The law of reflection states that the angle of incidence = the angle of reflection.
Explanation:
Reflection is the phenomenon that occurs when a ray of light hits the boundary between two media and it is reflected back into the first medium.
In such a situation, we call:
- angle of incidence: it is the angle between the direction of the incident ray and the normal to the surface
- angle of reflection: it is the angle between the direction of the reflected ray and the normal to the surface
There is a precise relationship between the angle of incidence and the angle of reflection. In fact, the Law of Reflection states that:
- The incident ray, the reflected ray and the normal to the surface all lie within the same plane
- The angle of reflection is equal to the angle of incidence
Answer:
0.650
Explanation:
Move the decimal point three times to the left.
Answer:
A 10 N force pointing up
Explanation:
If the net acceleration of the object is horizontal pointing to the right, that means that all vertical forces must have canceled out, and the only ones "unbalanced" are the horizontal ones (10 N to the right minus 5 N to the left giving a net force of 5 N to the right).
Since they mentioned only one vertical force pointing down (10 N), there must be another one of same magnitude but pointing in opposite direction (up).
Then there must also be a 10 N force pointing up acting on the object.
200 Hz = 200 cycles per sec
<span>1 cycle, the period = 1/200 = 0.005 seconds, or 5 milli seconds.</span>
