B. Wagon B will accelerate at twice the rate as Wagon A. hope this helps!
Answer:
0.0034 sec
Explanation:
L = initial length
T = initial time period = 2.51 s
Time period is given as
![T = 2\pi \sqrt{\frac{L}{g}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7BL%7D%7Bg%7D%7D)
![2.51 = 2\pi \sqrt{\frac{L}{9.8}}](https://tex.z-dn.net/?f=2.51%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8%7D%7D)
L = 1.56392 m
L' = new length
ΔT = Rise in temperature = 142 °C
α = coefficient of linear expansion = 19 x 10⁻⁶ °C
New length due to rise of temperature is given as
L' = L + LαΔT
L' = 1.56392 + (1.56392) (19 x 10⁻⁶) (142)
L' = 1.56814 m
T' = New time period
New time period is given as
![T' = 2\pi \sqrt{\frac{L'}{g}}](https://tex.z-dn.net/?f=T%27%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7BL%27%7D%7Bg%7D%7D)
![T' = 2\pi \sqrt{\frac{1.56814}{9.8}}](https://tex.z-dn.net/?f=T%27%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7B1.56814%7D%7B9.8%7D%7D)
T' = 2.5134 sec
Change in time period is given as
ΔT = T' - T
ΔT = 2.5134 - 2.51
ΔT = 0.0034 sec
Answer:
75degree don't forget wind and gravity force pulling down
3. Sand has a low specific heat compared to air
Answer:
Acceleration is 0.25m/s^2
Explanation:
Given the following :
Speed = 0.5m/s
Radius(r) of circle = 1m
Acceleration round a circular path is given as :
a = v^2 / r
Where
a = acceleration of the body
v = speed / velocity
r = radius
Therefore,
a = v^2 / r
a = (0.5)^2 / 1
a = 0.25m/s^2