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seraphim [82]
3 years ago
13

(a) what is meant by diffusion? give one example of diffusion in gases. ​

Chemistry
2 answers:
yanalaym [24]3 years ago
7 0

Answer:

The gases which dissolve in water by diffusion are carbon dioxide and oxygen.

Explanation:

HAVE A GOOD DAY!

Drupady [299]3 years ago
5 0
A) The mixing of a substance with another substance due to the motion or movement of its particles is called diffusion.
b) Gaseous particles tend to undergo diffusion because they have kinetic energy.
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In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
Yuliya22 [10]
The balanced chemical equation is:

2H2 + O2 ---> 2H2O

We are given the amount of the product produced from the reaction. This will be the starting point for the calculations.

355 g H2O ( 1 mol H2O/ 18.02 g H2O) ( 1 mol O2 / 2 mol H2O ) ( 32 g O2 / 1 mol O2 ) = 315.205 g O2
6 0
3 years ago
A vessel of volume 100ml contains 10% of oxygen and 90% of an unknown gas. The gases diffuses in 86 second through a small hole
swat32

The molecular weight of unknown gas : 23.46 g/mol

<h3>Further explanation</h3>

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

\tt 0.1\times 32+0.9\times M=3.2+0.9M

Graham's Law :

\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol

7 0
3 years ago
Name a possible product of this reaction in the presence of ether and AlCl3: methylbenzene + 1-chlorodecane.a. 1-methyl-2-decylb
Vikki [24]

Answer:

None of these

Explanation:

Friedel–Craft reaction is a reaction involves the attachment of substituents to the benzene ring.

Mechanism of the reaction of methylbenzene with 1-chlorodecane in the presence of ether and aluminum chloride :

Step -1 : Generation of stable carbocation.

Aluminium chloride acts as Lewis acid which removes the chloride ion from the alkyl halide forming carbocation. The primary carbocation thus formed gets rearranged to secondary primary carbocation which is more stable due to hyperconjugation.

Step-2: Attack of the ring to the carbocation

The pi electrons of the ring behave as a nucleophile and attacks the carbocation. Since, the group attached on the benzene is methyl (+R effect) , the attack is from the ortho and the para positions. Para product is more stable due to less steric hinderance.

The product formed is shown in mechanism does not mention in any of the options.

So, None of these is the answer

8 0
4 years ago
Read 2 more answers
On the basis of which property of the elements are they divided in metals and non metals?​
kifflom [539]

Answer:

There are many properties that differentiate metals from non-metals. They are: Luster, conductivity of heat and electricity, physical strength i.e. Brittle or difficult to break, etc.

6 0
3 years ago
The body of knowledge that deals with Earth and its place in the universe is called _____________?
lakkis [162]

Answer:

Cosmology is a branch of astronomy that involves the origin and evolution of the universe, from the Big Bang to today and on into the future. According to NASA, the definition of cosmology is "the scientific study of the large scale properties of the universe as a whole."

7 0
2 years ago
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