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goldfiish [28.3K]
3 years ago
8

a 25 kg object is pushed with a horizontal force of 5 N esat across a table. If the force of friction is 2 N, what is the accele

ration of the object?
Physics
1 answer:
Julli [10]3 years ago
8 0

Answer:

Apply Newton's second law in the moving direction.

Explanation:

\begin{aligned}F &= ma\\5N-2N &= 25kg\times a\\a & = \frac{3N}{25kg}\\&= 0.12ms^{-2}\end{aligned}

Friction force applies in the opposite direction of motion; as a restriction.

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Two identical cars A and B are at rest on a loading dock with brakes released. Car C, of a slightly different style but of the s
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Answer:

Explanation:

Let the velocity after first collision be v₁ and v₂ of car A and B . car A will bounce back .

velocity of approach = 1.5 - 0 = 1.5

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adding two equation

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During second collision , B will collide with stationary A . Same process will apply in this case also. Let velocity of B and A after collision be v₃ and v₄.

For second collision ,

coefficient of restitution = velocity of separation / velocity of approach

.5 = v₃ + v₄ / 1.35

v₃ + v₄ = .675

applying law of conservation of momentum

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1.35 = v₄ - v₃

adding two equation

2 v ₄= 2.025

v₄ = 1.0125 m /s

v₃ = - 0 .3375  m / s

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