Most atoms are stable when they have _____ electrons in their outer shell

Given the setup of the equilibrium constant expression, a reaction that has a high equilibrium constant will "favor" the product

ss7ja [257]

Answer:

for points

Explanation:

loll

5 0

3 years ago

Question 10 of In which way does a balanced chemical equation demonstrate the conservation of matter? A. It shows the same numbe

prisoha [69]

Answer:

it’s probably c

Explanation:

3 0

3 years ago

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In order for a high temperature boiler or steam engine to produce superheated water, or steam: the heat source must be greater t

Vinil7 [7]

Answer:

the heat source must be greater than 100°C

the water must be permitted to evaporate quickly

the system must be sealed and become pressurized above atmospheric pressure

the vapor pressure must be kept below 760 mmHg

Explanation:

A superheated water is a dry form of steam in which hydrogen bonds that strongly binds the molecules of water has been overcome.

Superheated water finds application in a wide range of places. For example they are used for sterilization of clinical equipment.

To produce steam or superheated water, the temperature of the source must be greater than the boiling temperature and less than the critical temperature at 374°C.
Since superheated water is steam and steam is water in gaseous form. The water must be made to evaporate more quickly than it should condense back.
High pressure and sealing the system helps to produce superheated water very fast.
If the pressure between the vapor is kept low, water will boil faster.

8 0

3 years ago

An empirical research method in which data are gathered from observations of phenomena, hypothesis are formulated and tested, an

ahrayia [7]

Answer:

Scientific Method

Explanation:

Science is empirical in nature. The entire purpose of science is to discover new knowledge.

The empirical research method in science all begins with gathering observations from phenomena. After that, the researcher formulates appropriate hypothesis which are rigorously tested.

The conclusions drawn from testing the original hypothesis validate or modify the original hypothesis.

8 0

3 years ago

compound consists of carbon, hydrogen and fluorine. In one experiment, combustion of 2.50 g of the compound produced 3.926 g of

arlik [135]

Answer: The empirical and molecular formula of the compound is $CH_2F$ and $C_{14}H_{28}F_{14}$ respectively

Explanation:

We are given:

Mass of $CO_2=3.926g$

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.926 g of carbon dioxide, $\frac{12}{44}\times 3.926=1.071g$ of carbon will be contained.

To calculate the percentage composition of element in sample, we use the equation:

$\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100$ ......(1)

For Carbon:

Mass of carbon = 1.071 g

Mass of sample = 2.50 g

Putting values in equation 1, we get:

$\%\text{ composition of carbon}=\frac{1.071g}{2.50g}\times 100=42.84\%$

For Fluorine:

Mass of fluorine = 2.54 g

Mass of sample = 5.00 g

Putting values in equation 1, we get:

$\%\text{ composition of fluorine}=\frac{2.54g}{5.00g}\times 100=50.8\%$

Percent composition of hydrogen = [100 - 42.84 - 50.8] % = 6.36 %

We are given:

Percentage of C = 42.84 %

Percentage of F = 50.8 %

Percentage of H = 6.36 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 42.84 g

Mass of F = 50.8 g

Mass of H = 6.36 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.84g}{12g/mole}=3.57moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{6.36g}{1g/mole}=6.36moles$

Moles of Fluorine = $\frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{50.8g}{19g/mole}=2.67moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.67 moles.

For Carbon = $\frac{0.072}{2.67}=1.34\approx 1$

For Hydrogen = $\frac{6.36}{2.67}=2.38\approx 2$

For Fluorine = $\frac{2.67}{2.67}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : F = 1 : 2 : 1

The empirical formula for the given compound is $CH_2F$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 448.4 g/mol

Mass of empirical formula = $12+(2\times 1)+19]=33g/mol$

Putting values in above equation, we get:

$n=\frac{448.4g/mol}{33g/mol}=13.6\approx 14$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(14\times 1)}H_{(14\times 2)}F_{(14\times 1)}=C_{14}H_{28}F_{14}$

Hence, the empirical and molecular formula of the compound is $CH_2F$ and $C_{14}H_{28}F_{14}$ respectively

3 0

3 years ago