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Schach [20]
3 years ago
8

Both isopropyl alcohol, C3H8OH, and ethylene glycol, C2H6O2, are used as antifreeze. When equal masses of each are added to wate

r, which, if either, will be more effective at preventing freezing? A. Isopropyl alcohol B. Ethylene glycol C. They will produce the same effect D. Neither, because they do not dissolve in water.
Chemistry
2 answers:
kiruha [24]3 years ago
6 0
I believe the correct answer from the choices listed above is option B. When equal masses of each are added to water, ethylene glycol would be more effective. Ethylene glycol is the most widely used automotive cooling-systemantifreeze, although methanol, ethanol, isopropyl alcohol, and propylene glycol are also used.
Hope this answers the question. Have a nice day.
blagie [28]3 years ago
5 0
Hello there.

<span>Both isopropyl alcohol, C3H8OH, and ethylene glycol, C2H6O2, are used as antifreeze. When equal masses of each are added to water, which, if either, will be more effective at preventing freezing? 

</span><span>B. Ethylene glycol </span>
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A kid on a playground swing makes 6 complete to-and-fro swings each 30 seconds.
Virty [35]
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6 0
3 years ago
A bar of copper has a mass of 216g and a volume of 24cm^3. What is the density of copper?
7nadin3 [17]

Answer:

<h2>The answer is 9 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 216 g

volume = 24 cm³

The density is

density  =  \frac{216}{24}   \\

We have the final answer as

<h3>9 g/cm³</h3>

Hope this helps you

3 0
3 years ago
Is it possible to have a relative atomic mass less then 24 or more than 26
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6 0
4 years ago
In the summer of 2016, the city of Columbus Dublin Road Water Treatment plan exceeded the regulatory level of nitrate, which is
Verizon [17]

Answer:

a) 10 mg NO_3^-/L

b) 1.61*10^{-4}mol NO_3^-/L

c) 2.26 mg N/L

Carbon: C=26.64 \frac{mg C}{L}

Explanation:

<u>Nitrate</u>

First of all, is important to know that:

1 ppm=1 mg/L

a) 10 ppm of nitrate (NO_3^-) is equal to 10 mg NO_3^-/L

b) The molecular weight of nitrate is 62 g NO_3^-/mol

10 mg NO_3^-/L=0.01 g NO_3^-/L

\frac{0.01 g NO_3^-/L}{62 g NO_3^-/mol}=1.61*10^{-4} mol NO_3^-/L

c) Nitrate has 14 mg of N per 62 mg of NO3

10 mg NO_3^-/L*\frac{14 mg N}{62 mg NO_3^-}=2.26 mg N/L

<u>Carbon</u>

Carbonate has 12 mg of C per 60 mg of CO_3^{-2}

Bicarbonate has 12 mg of C per 61 mg of HCO_3^{-}

C=24 \frac{mg CO_3^{-2}}{L}*\frac{12 mg C}{60 mg CO_3^{-2}}+111 \frac{mg HCO_3^{-}}{L}*\frac{12 mg C}{61 mg HCO_3^{-}}

C=26.64 \frac{mg C}{L}

8 0
3 years ago
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