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andreyandreev [35.5K]
3 years ago
10

Identify which type of source is being described.

Physics
2 answers:
zavuch27 [327]3 years ago
7 0

Answer:

Identify which type of source is being described.

✔ Primary

sources present original research, whereas

✔ secondary

sources summarize scientific information.

Second Part----

Indicate whether each of the following is a primary source or a secondary source.

An article in Journal of the American Medical Association:  

✔ primary source

An article in Time magazine:  

✔ secondary source

An article in The New York Times newspaper:  

✔ secondary source

Explanation:

Just did the problem.

frez [133]3 years ago
3 0

Answer:

Primary, secondary

Explanation:

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D) diffraction

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This phenomenon produces one or more diffuse concentric rings of light around the Sun or Moon, usually seen as colored circles.

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Which of the following has the largest m/mentum?
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Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init
Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ=(m+\frac{1}{2})\frac{lamda}{n}  ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= \frac{3*lamda}{2}

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= \sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }

δ= \sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}

δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

δ= \sqrt{4900+43^2}-\sqrt{4900+23^2}

δ= \sqrt{4900+1849}-\sqrt{4900+529}

δ= \sqrt{6749}-\sqrt{5429}

δ=  82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= \frac{3*lamda}{2}

δ= 8.47

8.47 = \frac{3*lamda}{2}

λ = \frac{8.47*2}{3}

λ = 5.65m

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