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Arisa [49]
3 years ago
11

Which of the following values are solutions to the inequality 6<x+21, -4 2,4 3,0​

Mathematics
2 answers:
3241004551 [841]3 years ago
7 0

Answer:

4

Step-by-step explanation:

6<x+2 original

6-2<x subtract 2 from both sides

4>x flip the sign because we subtracted from both sides

4>x final, any number greater than 4 is X

checking:

plug in any value greater than 4 into x, for example, lets use 5

6<x+2

6<5+2

6<7   6 is less than 7, this is true the equasion works

pogonyaev3 years ago
3 0

Answer:

What are the options I will figure it out

Step-by-step explanation:

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If P is the incenter of triangle JKL, find the measure of JKP.
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Answer:

m∠JKP = 31.5°

Step-by-step explanation:

Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.

JN is the angle bisector of ∠KJL.

Therefore, m∠KJN = m∠LJN

(7x - 6) = (5x + 4)

7x - 5x = 6 + 4

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m∠KJN = (7x - 6)

            = 7(5) - 6

            = 35 - 6

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In ΔKJN,

m∠JKN + m∠KNJ + m∠NJK = 180°

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m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = \frac{1}{2}(\angle JKN)

            = \frac{1}{2}(61)

            = 30.5°

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