Magnetic field is produced by the magnet which will flow through any attractive item or even substance such as ferrofluid. Happy I could help:)
Answer
79.8 miles per hours fast is the car going.
Formula
By using the dopplers effect. (When source is approching .)
![f_{observed} = f_{source}(\frac{v}{v - v_{source}} )](https://tex.z-dn.net/?f=f_%7Bobserved%7D%20%3D%20f_%7Bsource%7D%28%5Cfrac%7Bv%7D%7Bv%20-%20v_%7Bsource%7D%7D%20%29)
As given
A car approaches you with its horn blowing.
The observed frequency is 503.7 Hz.
The speed of sound is 1100 ft/s .
The car's horn has a frequency of 450 Hz.
i.e
![f_{observed} = 503.7 Hz](https://tex.z-dn.net/?f=f_%7Bobserved%7D%20%3D%20503.7%20Hz)
v = 1100 ft/s
![f_{source} = 450 Hz](https://tex.z-dn.net/?f=f_%7Bsource%7D%20%3D%20450%20Hz)
Put in the above formula
![503.7= 450\times \frac{1100}{1100 - v_{source}}](https://tex.z-dn.net/?f=503.7%3D%20450%5Ctimes%20%5Cfrac%7B1100%7D%7B1100%20-%20v_%7Bsource%7D%7D)
![503.7\times {1100 - v_{source}=450\times 1100](https://tex.z-dn.net/?f=503.7%5Ctimes%20%7B1100%20-%20v_%7Bsource%7D%3D450%5Ctimes%201100)
![554070- 503.7v_{source}=495000](https://tex.z-dn.net/?f=554070-%20503.7v_%7Bsource%7D%3D495000)
![554070-495000=503.7v_{source}](https://tex.z-dn.net/?f=554070-495000%3D503.7v_%7Bsource%7D)
![59070=503.7v_{source}](https://tex.z-dn.net/?f=59070%3D503.7v_%7Bsource%7D)
![v_{source}= \frac{59070}{503.7}](https://tex.z-dn.net/?f=v_%7Bsource%7D%3D%20%5Cfrac%7B59070%7D%7B503.7%7D)
![v_{source}= 117.3\ ft\ per\ s(Approx)](https://tex.z-dn.net/?f=v_%7Bsource%7D%3D%20117.3%5C%20ft%5C%20per%5C%20s%28Approx%29)
Now convert 117.3 ft per second into miles per hours.
![1\ foot = \frac{1}{5280}\ miles](https://tex.z-dn.net/?f=1%5C%20foot%20%3D%20%5Cfrac%7B1%7D%7B5280%7D%5C%20miles)
![1\ hours = \frac{1}{3600}\ hours](https://tex.z-dn.net/?f=1%5C%20hours%20%3D%20%5Cfrac%7B1%7D%7B3600%7D%5C%20hours)
![\frac{117.3\ feet}{second} = \frac{117.3\times \frac{1}{5280}\ miles}{\frac{1}{3600}\ hours}](https://tex.z-dn.net/?f=%5Cfrac%7B117.3%5C%20feet%7D%7Bsecond%7D%20%3D%20%5Cfrac%7B117.3%5Ctimes%20%5Cfrac%7B1%7D%7B5280%7D%5C%20miles%7D%7B%5Cfrac%7B1%7D%7B3600%7D%5C%20hours%7D)
![\frac{117.3\ feet}{second} = \frac{0.022216\ (Approx)}{0.00028\ (Approx)}](https://tex.z-dn.net/?f=%5Cfrac%7B117.3%5C%20feet%7D%7Bsecond%7D%20%3D%20%5Cfrac%7B0.022216%5C%20%28Approx%29%7D%7B0.00028%5C%20%28Approx%29%7D)
117.3 feet per second = 79.8 miles per hours (Approx)
Thus
![v_{source}= 79.8\ miles\ per\ hours](https://tex.z-dn.net/?f=v_%7Bsource%7D%3D%2079.8%5C%20miles%5C%20per%5C%20hours)
Therefore the 79.8 miles per hours fast is the car going.
Answer:
Acceleration
![\frac{distace}{time}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdistace%7D%7Btime%7D%20)
When we cross multiply, distance will be equal to acceleration multiply by time
Distance = acceleration x time
Distance = 9.8 x 3
= 29.4 m/s
Answer:
Explanation:
Since the bell is at rest in an elevated position, we can assume that it only has potential energy.
U=mgh is the formula for potential energy where U=potential energy, m= mass, g=acceleration due to gravity, and h=height.
Plug in known variables....
U=200kg*9.8m/s^2*45m
U=88200 joules of potential energy or letter D.