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kakasveta [241]
3 years ago
14

Suppose the Moon rose at 6 p.m. yesterday. What are the approximate rising times and phase of the Moon today?

Physics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

The moon will rise around 6:50 pm today, and it's a warning gibbous, just a day or two past full.

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How do you think that changing the mass of the pendulum bob will affect the period of the pendulum swing?​
myrzilka [38]
(Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.)
5 0
3 years ago
Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass g
djyliett [7]

Answer:

a) m = 69.0 kg

b) release some gas in the opposite direction to the astronaut's movement

Explanation:

a) Let's use Newton's second law

         F = m a

         m = F / a

         m = 60.0 / 0.870

         m = 69.0 kg

b) when we exert a force on the astronaut it acquires a momentum po, as the astronaut system plus spacecraft is isolated, the momentum is conserved

         p₀ = p_f

         m v = M v '

         v ’= \frac{m}{M} \ v

so we see that the ship is moving backwards, but since the mass of the ship is much greater than the mass of the astronaut, the speed of the ship is very small.

One method to avoid this effect is to release some gas in the opposite direction to the astronaut's movement so that the initial momentum of the astronaut plus the gas is zero and therefore no movement is created in the spacecraft.

3 0
2 years ago
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Artyom0805 [142]
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7 0
2 years ago
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Sally and Sam are in a spaceship that comes to within 17,000 km of the asteroid Ceres. Determine the force Sally experiences, in
MAXImum [283]

Answer:

0.01606 Newtons

Explanation:

r = Distance between the asteroid and Sally = 17000000 m

m₁ = Mass of the asteroid = 8.7× 10²⁰ kg

m₂ = Mass of Sally = 80 kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

From Newton's Universal law of gravity

F=G\frac{m_1m_2}{r^2}\\\Rightarrow F=6.67\times 10^{-11}\times \frac{8.7\times 10^{20}\times 80}{17000000^2}\\\Rightarrow F=0.01606\ N

The force Sally experiences is 0.01606 Newtons

8 0
3 years ago
A projectile is launched with a velocity of 13.2m/s at an angle of 37 degrees above the horizontal. What is the horizontal compo
MrRissso [65]

Answer:

horizontal component = 10.54m/s

Explanation:

horizontal component = 13.2cos37°

horizontal component = 10.54m/s

8 0
3 years ago
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