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marta [7]
3 years ago
7

It takes 5.0 seconds for a wave with a wavelength of 2.5 m to travel past your location. What’s the period of the wave. What is

the frequency of the wave and what’s the speed of the wave
Physics
1 answer:
Anna35 [415]3 years ago
8 0
(a) Period of the wave
The period of a wave is the time needed for a complete cycle of the wave to pass through a certain point.
So, if an entire cycle of the wave passes through the given location in 5.0 seconds, this means that the period is equal to 5.0 s: T=5.0 s.

(b) Frequency of the wave
The frequency of a wave is defined as
f= \frac{1}{T}
since in our problem the period is T=5.0 s, the frequency is
f= \frac{1}{5.0 s}=0.2 Hz

(c) Speed of the wave
The speed of a wave is given by the following relationship between frequency f and wavelength \lambda:
v=f \lambda = (0.2 Hz)(2.5 m)=0.5 m/s

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A piston above a liquid in a closed container has an area of 0.75m^2, and the piston carries a load of 200kg. What will be the e
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2613.3 pa

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6 0
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A uniform cylindrical grindstone has a mass of 15.0 kg and a radius of 18.6 cm. The grindstone reaches a rotational velocity of
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Answer:

n \approx 5.778\times 10^{-4}\,rev

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The Work-Energy Theorem is applied herein:

-\frac{1}{4}\cdot m_{cyl}\cdot R^{2}\cdot \omega^{2} = - \mu_{k}\cdot N\cdot r \cdot 2\pi \cdot n

The number of turns needed to stop the grindstone is:

n = \frac{m_{cyl}\cdot R^{2}\cdot \omega^{2}}{4\cdot \mu_{k}\cdot N \cdot r\cdot 2\pi}

n = \frac{(15\,kg)\cdot (0.186\,m)^{2}\cdot [(1.83\,\frac{rev}{min} )\cdot (\frac{2\pi\,rad}{1\,rev} )\cdot (\frac{1\,min}{60\,s} )]^{2}}{4\cdot (0.80)\cdot (8.82\,N)\cdot(0.186\,m)\cdot 2\pi}

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8 0
3 years ago
How do you graph distance and time for an object that moves at a constant speed?
LekaFEV [45]

Answer:

It would be a straight line

Explanation:

On a distance-time graph, an object that moves at constant speed would be represented by a straight line.

In fact, in a distance-time graph, the slope of the line corresponds to the speed of the object. We can demonstrate that. In fact:

- The speed of the object is equal to the ratio between the distance covered (\Delta s) and the time taken (\Delta t):

v=\frac{\Delta s}{\Delta t}

On a distance-time graph, the distance is on the y-axis while the time is on the x-axis. The slope of the line is defined as:

m=\frac{\Delta y}{\Delta x}

But the variation on the y-axis (\Delta y) is equal to the distance covered (\Delta s), while the variation on the x-axis (\Delta x) corresponds to the time taken (\Delta t), so the slope can also be rewritten as

m=\frac{\Delta s}{\Delta t}

which is equal to the speed of the object. Therefore, an object moving at constant speed would be represented by a line with constant slope, which means a straight line.

6 0
2 years ago
Read 2 more answers
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