Answer:
ν = 5.45 x 10¹⁴ Hz
Explanation:
given,
wavelength of light = 550 nm
= 550 x 10⁻⁹ m
speed of light = 1.96 x 10⁸ m/s
speed of sound = 3 x 10⁸ m/s
frequency of the light = ?
we know.
frequency of the light in the liquid is same as the frequency of the light in the air.
ν is the frequency of light
ν = 5.45 x 10¹⁴ Hz
Hence, the frequency of light in the liquid is equal to ν = 5.45 x 10¹⁴ Hz
Answer:
the andromeda galaxy
Explanation:
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Answer:
The answer to your question is given below.
Explanation:
From the diagram given in the question, we can see that the bulbs are in parallel connection. This implies that different current will go through the bulb but the same voltage. But the resistance of each bulb is the same, therefore the same current current will go through them.
This can further be understood if we determine the current flowing through each bulb. This is illustrated below:
Voltage (V) = 30V
Resistant 1 (R1) = 15Ω
Current 1 (I1) =..?
V = I1R1
30 = I1 x 15
Divide both side by 15
I1 = 30/15
I1 = 2A.
Voltage (V) = 30V
Resistant 2 (R2) = 15Ω
Current 2 (I2) =..?
V = I2R2
30 = I2 x 15
Divide both side by 15
I2 = 30/15
I2 = 2A.
The overall current(I) in the circuit:
I = I1 + I2
I = 2 + 2 = 4A.
From the illustrations above, we can see that the same current will flow through each bulb as the will current split into two equal parts
Answer:
The correct option is A.
Explanation:
Following the equation of continuum, AV remains constant.
Case a
(3A)(V0) = AV1 + AV1 + AV1
3AV0 = 3AV1
V1 = V0
Case b
(A)(V0) = (A/3)V2 + (A/3)V2 + (A/3)V2 + (A/3)V2
AV0 = 4V2/3
V2 = 3/4V0
Case c
(A/2)(V0) = AV3 + AV3 + AV3
AV0/2 = 3AV3
V3 = V0/6
Case d
(3A)(V0) = 2AV4 + 2AV4
3AV0 = 4AV4
V4 = 3V0/4
Comparing all the flow speeds, V1 is the largest.
Thus, the correct option is A.
