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2 years ago

Is krypton cation or anion?

Chemistry

1 answer:

tensa zangetsu [6.8K]2 years ago

6 0

Answer:

This makes it isoelectronic with krypton. The anion of bromine is Br-. The element rubidium has an electronic number 37. It loses one electron to gain a positive charge and change to Rb+ which has 36 electrons and is a cation that is isoelectronic with krypton

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CH, +<br> ,<br> 0, → _CO, +<br> Н,0<br> Balance chemical equation

Flura [38]

Answer:

2 CH2 + 3 O2 = 2 CO2 + 2 H2O

Explanation:

This is what I think that you meant by the question listed. When balancing a chemical equation, you want to make sure that there are equal amounts of each element on each side.

Originally, the equation's elements looked like this: 1 C on left & 1 C on right; 2 H on left & 2 H on right; 2 O on left and 3 O on right. Because these are not balanced, you need to add coefficients.

When adding coefficients, you need to make sure that all of the elements stay balanced, not just one that you are trying to fix. I know that some equations are really difficult to balance, and when that is the case, there are equation balancing websites that can help out.

However, what always helps me is making a chart and continuing to keep up with the changes I am making. It is a trial and error process.

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2 years ago

In an exothermic reaction, the water will _______ in a calorimeter.

professor190 [17]

In an exothermic reaction, the water will increase in temperature in a calorimeter. An exothermic reaction is a reaction where heat is one of the products or heat is being released from it which will cause for the temperature inside the calorimeter to increase.

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2 years ago

What is (2.5x10²)² =

siniylev [52]

The answer is 6.25 x 10^4.

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2 years ago

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Give the name and formula of the compound formed when a Mn2+ cation combines with a (PO4)3- anion

alex41 [277]

Sodium mn2 and po4 makes sodium

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3 years ago

The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

motikmotik

The allowable combination for the atomic orbital is n=3, l=1, $m_{l}$ =-1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; $m_{l}$ values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Since $m_{l}$ values are integers from -l to 0 to +l, for l = 0 the value of $m_{l}$ cannot be -1 (l = 0 has $m_{l}$ = 0).

There are two l values that are consistent with n and $m_{l}$ values:

l=1 or 2

Therefore, the allowable condition is n=3, l=1, $m_{l}$ =-1.

To know more about quantum numbers, visit: brainly.com/question/16979660

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1 year ago