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monitta
2 years ago
14

Pedigree charts use shaded symbols to show organisms that have a particular trait, such as a defective gene, being traced in the

chart. A breeder wants to make a pedigree chart of male horses to avoid breeding males that have a defective gene. What symbol would the horse breeder use to show a male who is affected by a defective gene?
Chemistry
2 answers:
Ulleksa [173]2 years ago
5 0
Males are represented my a square
if he is affected by a defective gene he should show a shaded square that differs from normal males just like this■
xxMikexx [17]2 years ago
4 0

Answer:  A male who is affected by a defective gene would have a symbol of shaded square that the horse breeder would use in the pedigree that is ■.

Pedigree can be described as a representation of a family and its lineage ( that is its ancestory and line of descent) in a form of flow chart ( using standard symbols), which depicts the pattern of inheritance of a particular disease.

For a male, a symbol of square is used and for a female, a symbol of square is used  ( that are shaded if the individuals are affected with a disease)

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Answer:

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Missing: 45.65 ‎| ‎Must include: ‎45.65

Explanation:

6 0
3 years ago
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Pie

Answer: <u>A integer is a whole number.</u>

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Explanation:

i hope this answer your question if this is wrong or correct please let me know

5 0
2 years ago
What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi
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Explanation:

Formula to calculate standard electrode potential is as follows.

          E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}

                             = 0.535 - 1.065

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Also, it is known that relation between E^{o}_{cell} and K is as follows.

            E^{o}_{cell} = \frac{RT}{nF} \times ln K

                 ln K = \frac{nFE^{0}_{cell}}{RT}      

Substituting the given values into the above formula as follows.

                 ln K = \frac{nFE^{0}_{cell}}{RT}    

                        =  \frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}  

                ln K = -41.28

                    K = e^{-41.28}    

                        = 1 \times 10^{-18}

Thus, we can conclude that the value of the equilibrium constant for the given reaction is 1 \times 10^{-18}.      

5 0
3 years ago
) Calculate the number of moles of sulfuric acid that is contained in 250 mL of 0.500 M sulfuric acid solution
maksim [4K]

Explanation:

According to the analysis, Molarity is amount mole per volume(1L). the amount in mole would be molarity × volume in litres.

0.500M × (250/1000)L= 0.125moles.

I hope this helps**

3 0
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