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leonid [27]
2 years ago
8

Given the molecules diethyl ether (CH₃CH₂OCH₂CH₃) and 1-butanol (CH₃CH₂CH₂CH₂OH), __________ has the higher boiling point mainly

due to __________.
Chemistry
2 answers:
Anna71 [15]2 years ago
4 0

Answer:117 degree Celsius

Explanation: this is due to the hydrogen bonding between the OH of the alcohol

MArishka [77]2 years ago
3 0

Answer:

1-butanol has higher boiling point mainly due to presence of hydrogen bonding.

Explanation:

Diethyl ether is a polar aprotic molecule due to presence of polar C-O-C moiety. Hence only dipole-dipole intermolecular force exist between diethyl ether molecules.

1-butanol is a polar protic molecule due to presence of C-OH moiety. Therefore dipole-dipole force along with hydrogen bonding exist between 1-butanol molecules.

So, intermolecular force is higher in 1-butanol as compared to diethyl ether. Hence more temperature is required to break intermolecular forces of 1-butanol to boil as compared to diethyl ether.

So, 1-butanol has higher boiling point mainly due to presence of hydrogen bonding.

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a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g
leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

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By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

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harkovskaia [24]

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<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

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8 0
3 years ago
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