Answer:
The answer to your question is C = 1.116 J/g°C
Explanation:
Data
Q = 400 J
mass = 5.6 g
Temperature 1 = T1 = 23°C
Temperature 2 = T2 = 87°C
Specific heat = C = ?
Formula
Q = mC(T2 - T1)
- Solve for C
C = Q / m(T2 - T1)
- Substitution
C = 400 / 5.6 (87 - 23)
- Simplification
C = 400 / 5.6(64)
C = 400 / 358.4
- Result
C = 1.116 J/g°C
Dark energy and dark matter seem over analyzed, although they are no different than gravity and wind. Dark energy can be the pulling caused by black holes, stars, and large planets. Dark matter also is just the effect of cosmic dust and debris pushed from explosions but also pulling caused by distant gravitational bodies.
Answer:
From the Online Catalog to the Shelf
Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.
Explanation:
Answer:
141.0 g NaN₃.
Explanation:
It is a stichiometric problem.
Firstly, we should wright the reaction as a balanced equation:
2NaN₃ → 2Na + 3N₂
It is clear that 2.0 moles of NaN₃ decompose to 2.0 mole of Na and 3.0 moles of N₂.
Then we should convert the volume of N₂ (70.0 L) to moles via using the gas law of ideal gas: PV = nRT, n = PV / RT,
Where, P is the pressure of the gas in atm (P = 1.2 atm).
V is the volume of the gas in L(V = 70.0 L).
R is the general gas constant (R = 0.082 L.atm/mol.K).
T is the temperature in K(T = 315 K).
∴ n of N₂ = PV / RT = (1.2 atm) (70.0 L) / (0.082 L.atm/mol.K) (315 K) = 3.252 mole.
From the stichiometry:
2.0 moles of NaN₃ decomposes to → 3.0 moles of N₂
??? mole of NaN₃ decomposes to → 3.2520 moles of N₂
The number of moles of NaN₃ = (2.0 moles of NaN₃) (3.2520 moles of N₂) / (3.0 moles of N₂) = 2.168 mole.
Finally, we can convert the number of moles of NaN₃ to mass using the relation: m = n x molar mass.
Molar mass of NaN₃ = 65.0 g/mol.
the mass of NaN₃ = n x molar mass = (2.168 mole) (65.0 g/mol) = 140.92 g ≅ 141.0 g.
