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Alex73 [517]
3 years ago
13

What causes differences in air pressure

Chemistry
2 answers:
shtirl [24]3 years ago
5 0
Unequal heating of the atmosphere
LiRa [457]3 years ago
4 0

Answer:

D.

Explanation:

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Why is acetic acid written as hc2h3o2 rather than c2h4o2?
Naddik [55]
<span>Acetic acid is under the family of carboxylic acids which has a carboxyl group –COOH bond attached to the alkyl group. Alkyl group can be methyl (CH3-), ethyl (CH3CH2-) and so on. The term acetic also means methyl. So combining the two gives CH3COOH or HCH3CO2. The H before the C in <u>H</u>CH3CO2 means that it is the H attached to the O in the carboxyl group –COOH. You cannot write it as C2H4O2 because it would represent a different compound.</span>
8 0
3 years ago
How do bubbles support the atomic theory?
Tpy6a [65]
A. The bubbles are lighter than air.
B. There is matter that cannot be seen inside the bubbles.
C. The bubbles will burst before long.
D. The bubbles cannot be broken into smaller pieces.
3 0
3 years ago
Analysis of a rock sample shows that it contains 6.25% of its original uranium-235. How old is the rock? How do you know?
nadya68 [22]

Answer:

2.82\cdot 10^9 y

Explanation:

A radioactive isotope is an isotope that undergoes nuclear decay, breaking apart into a smaller nucleus and emitting radiation during the process.

The half-life of an isotope is the amount of time it takes for a certain quantity of a radioactive isotope to halve.

For a radioactive isotope, the amount of substance left after a certain time t is:

m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}} (1)

where

m_0 is the mass of the substance at time t = 0

m(t) is the mass of the substance at time t

\tau is the half-life of the isotope

In this problem, the isotope is uranium-235, which has a half-life of

\tau=7.04\cdot 10^8 y

We also know that the amount of uranium left in the rock sample is 6.25% of its original value, this means that

\frac{m(t)}{m_0}=\frac{6.25}{100}

Substituting into (1) and solving for t, we can find how much time has passed:

t=-\tau log_2 (\frac{m(t)}{m_0})=-(7.04\cdot 10^8) log_2 (\frac{6.25}{100})=2.82\cdot 10^9 y

5 0
4 years ago
Please help me with this homework
ella [17]

Answer:

Density is the correct answer choice.

5 0
3 years ago
Read 2 more answers
Nén 10l khi ở áp suất 1atn,nhiệt đọ 27độ c để thể tích của nó giảm còn 5 lít quá trình nén nhanh nên nhiệt độ tăng đến 57 độ c á
mariarad [96]

Answer:

Explanatio

pV=nRT

=>n =  0.4(mol)

=>p  2= 2.34 atm

8 0
3 years ago
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