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liraira [26]
3 years ago
11

if Combustion analysis of an unknown compound provides the following data: 98.28 grams of carbon, 16.21 grams hydrogen and 65.52

grams oxygen. what is the percent composition of carbon in this compound
Chemistry
1 answer:
inysia [295]3 years ago
7 0

Answer:

54.6%

Explanation:

Percentage composition of carbon in compound

= ( mass of carbon in compound / total mass of compound ) x100

= ( 98.28 / 98.28 + 16.21 + 65.52 ) x 100

= (98.28 / 180.01 ) x 100

= 54.6% (3sf)

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Calculate the amount of ATP in kg that is turned over by a resting human every 24 hours. Assume that a typical human contains ~5
valentinak56 [21]

Answer:

The correct answer is 66.35 kilograms.

Explanation:

Based on the data given in the question, the energy consumed by the body of a human being is 50%. Based on the given data, the energy consumed in a day is 8000 kJ, 50 percent is the energy transfer efficiency. Thus, the consumption of total energy is 4000 kJ, and for the transformation of ADP to ATP, the energy involved is 30.6 kJ per mole.  

Hence, the total ATP produced in the process is,  

ATP = 4000 kJ / 30.6 kJ/mol

= 130.7189 mol.  

Thus, with the energy transfer efficiency of 50 percent, the total moles of ATP produced is 130.7 mol.  

The mass of ATP can be calculated by using the formula,  

moles = mass/molecular mass

The molecular mass of ATP is 507.18 g per mol

Now by putting the values we get,  

mass of ATP = 130.7189 mol * 507.18 g/mol

= 66298.011 g or 66.298 kg

It is mentioned that human comprise 50 g of ATP or 0.05 kg of ATP. Therefore, the sum of the available ATP will be.  

= Total production of ATP + Total ATP available

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5 0
4 years ago
A 850.0 mL cylinder containing B2H6 at a pressure of 0.900 atm is connected by a valve to 1000 mL cylinder containing C6H6 at 60
8_murik_8 [283]

Answer:

The partial pressure of C_6H_6 when the valve is opened is 328.6 Torr.

Explanation:

Initial pressure of the C_6H_6=P_1=608.0 Torr

Initial volume of the C_6H_6=V_1=1000 mL

After opening the valve :

Final pressure or partail pressure of the C_6H_6=P_2

Final volume of the C_6H_6=V_2=1000 mL+850.0 mL=1850.0 mL

P_1V_1=P_2V_2 ( Boyle's law)

P_2=\frac{608.0 Torr \times 1000 mL}{1850.0 mL}=328.6 Torr

The partial pressure of C_6H_6 when the valve is opened is 328.6 Torr.

4 0
3 years ago
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