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liraira [26]
3 years ago
11

if Combustion analysis of an unknown compound provides the following data: 98.28 grams of carbon, 16.21 grams hydrogen and 65.52

grams oxygen. what is the percent composition of carbon in this compound
Chemistry
1 answer:
inysia [295]3 years ago
7 0

Answer:

54.6%

Explanation:

Percentage composition of carbon in compound

= ( mass of carbon in compound / total mass of compound ) x100

= ( 98.28 / 98.28 + 16.21 + 65.52 ) x 100

= (98.28 / 180.01 ) x 100

= 54.6% (3sf)

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As a technician in a large pharmaceutical research firm, you need to produce 250. mL of a potassium dihydrogen phosphate buffer
Reika [66]

Answer:

We will need 147.772 mL of KH2PO4 to make this solution

Explanation:

For this case we can give the following equation:

H2PO4 - ⇄ H+ + HPO42-

With following pH- equation:

pH = pKa + log [HPO42-]/[H2PO4-]

7.05 = 7.21 + log [HPO42-]/[H2PO4-]

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10^-0.16 = [HPO42-]/[H2PO4-]

0.6918 = [HPO42-]/[H2PO4-]

Let's say the volume of HPO42-= x  then the volume of H2PO4- will be 250 mL - x

Since both have a concentration of 1M = 1 mol /L

If we plug this in the equation 0.6918 = [HPO42-]/[H2PO4-]

0.6918 = x / (250 - x)

0.6918*250 - 0.6918x = x

172.95 = 1.6918x

x = 102.228 mL

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Then the volume of H2PO4- = 250 - 102.228 = 147.772 mL

To control this we can plug this in the pH equation

7.05 = 7.21 + log [HPO42-]/[H2PO4-]

7.05= 7.21 + log (102.228 / 147.772) = 7.05

We will need 147.772 mL of KH2PO4 to make this solution

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3 years ago
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T is the temperature required (calculated in kelvin)

Using these values to substitute in the equation, we find that:

(1.8)(18.2) = (1.2)(0.0821)(T)

T = 332.5 degree kelvin

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Why are basic radicals classified into six groups?​
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