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liraira [26]
3 years ago
11

if Combustion analysis of an unknown compound provides the following data: 98.28 grams of carbon, 16.21 grams hydrogen and 65.52

grams oxygen. what is the percent composition of carbon in this compound
Chemistry
1 answer:
inysia [295]3 years ago
7 0

Answer:

54.6%

Explanation:

Percentage composition of carbon in compound

= ( mass of carbon in compound / total mass of compound ) x100

= ( 98.28 / 98.28 + 16.21 + 65.52 ) x 100

= (98.28 / 180.01 ) x 100

= 54.6% (3sf)

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Student Exploration: Limiting Reactants Vocabulary: chemical equation, chemical formula, chemical reaction, coefficient, limitin
SIZIF [17.4K]

Answer:

30 hot dogs

Explanation:

It is given that :

There are 4 packets of eight wieners, i.e. 4 x 8 = 32 wieners

There are 3 bags of ten buns, i.e. 3 x 10 = 30 buns

One hot dogs need 1 bun and 1 wiener to make a hot dog.

There are 30 buns, so 30 hot dogs can be made out by using all the 30 buns and the 30 wieners out of the 32 wieners.

Therefore, 30 hot dogs.

And the number of extra wieners left = 32 - 30 = 2 wieners.

6 0
2 years ago
Can any one please help me to answers this question i don't get it. thank in advance.
alex41 [277]
First, lets balance the reaction equation:
4Fe + 3O₂ → 2Fe₂O₃
It is visible form the equation that 4 moles of Fe require 3 moles of O₂
Molar ratio Fe/O₂ = 4/3 = 1.33
Molar ratio O₂/Fe = 3/4 = 0.75
Now, we check the molar ratios present:
Fe/O₂ = 6.8/8.9 = 0.76
O₂/Fe = 1.31

Thus, Iron is the limiting reactant because its ratio is not being fulfilled while the ratio of O₂ is surpassed.
8 0
3 years ago
How many atomospheres are in 710 mm Hg
timofeeve [1]

Answer:

0.934210526 atmospheres

Explanation:

5 0
2 years ago
Read 2 more answers
A 500-ml glass beaker is filled to the brim with ethyl alcohol at a temperature of 5. 00ºc. how much will overflow when its temp
Setler [38]

The volume of ethyl alcohol overflow will be 9.265mL.

To calculate the volume of ethyl alcohol overflow, we will use

∆V=V(á∆T)

Where,

∆V=volume expand

á=volumetric expansion Coefficients =0.00109/°C

V=initial volume =500ml

T'=final temp. =22°C

T=initial temp=5°C

Now,

∆V=500×(0.00109/°C) ×(22-5)

=500×(0.00109) (17)

=9.265ml

Thus, we find that the volume of ethyl alcohol overflow will be 9.265 mL.

learn more about ethyl alcohol:

brainly.com/question/11237501

#SPJ4

5 0
1 year ago
HELP QUICK!!!
madreJ [45]

Answer:

The 150 g Al will reach a higher temperature.

Explanation:

  • The amount of heat added to a substance (Q) can be calculated from the relation:

Q = m.c.ΔT.

where, Q is the amount of heat added,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the temperature difference (final T - initial T).

<em>Since, Q and c is constant, ΔT will depend only on the mass of the substance (m).</em>

∵ ΔT is inversely proportional to the mass of the substance.

∴ The piece with the lowest mass (150.0 g) will reach a higher temperature than that of a higher mass (250.0 g).

<em>So, the right choice is</em>: The 150 g Al will reach a higher temperature.

5 0
3 years ago
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