Answer:
b. ph is greatet than 7
Explanation:
ph=7 neutral
ph=7-14 basicity as you go up increase basicity
ph=0-7 acodity as you go down increasing acidity
Answer:
All the amounts of reactants and products are:
KBr
11.0g (given)
0.0924 mol
Cl₂
0.0462 mol
3.28g
KCl
0.0924 mol
6.89 g
Br₂
0.0462 mol
7.39 g
Explanation:
<u>1. Balanced chemical equation (given)</u>

<u>2. Mole ratios</u>



<u />
<u>3. Molar masses</u>
- Molar mass Cl₂: 70.906g/mol
- Molar mass KBr: 119.002 g/mol
- Molar mass KCl: 74.5513 g/mol
- Molar mass KBr: 159.808 g/mol
<u>4. Convert 11 grams of potassium bromide to moles:</u>
- #moles = mass in grams / molar mass
- #mol KBr = 11g / 119.002g/mol = 0.092435mol KBr
<u>5. Use the mole ratios to find the amounts of Cl₂, KCl, and Br₂</u>
a) Cl₂


b) KCl


c) Br₂


The final calculations are rounded to 3 sginificant figures.
Answer: 873 kJ of energy will be required to break two moles of hydrogen gas.

Above chemical equation shows that two moles of hydrogen gas is reacting with one mole of oxygen gas to give two mole of water molecule.
Bond energy of H-H = 436kJ
According to reaction we have two moles hydrogen,so energy required to break the
H-H bond in two moles of hydrogen gas will be:

= 872kJ
872kJ of energy will be required to break H-H bond in two moles of hydrogen gas.
Answer:
a) dissolving sugar in water to form a mixture of sugar and water
Explanation:
exothermic reaction is reaction in which is heat is released during the reaction and endothermic reaction is a reaction in which heat is needed or required for the reaction to take place
all the options excluding option A) is exothermic as during the process of formation of bonds in oxidation, heat is released. rusting too is a slow form of oxidation and thus an exothermic reaction.
dissolving sugar in water is not exothermic reaction because their is no heat released. the sugar molecules simply disperses in the water molecules and form a solution.
Answer:
The equation for this reaction is:
2Al(OH)3 (aq) + 3H2SO4 (l) ---> Al2(SO4)3 (s) + 6H2O (l)
Explanation: